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resource_request.go
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resource_request.go
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/*
Copyright 2019 The Tekton Authors
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/
package pod
import (
corev1 "k8s.io/api/core/v1"
"k8s.io/apimachinery/pkg/api/resource"
)
var emptyResourceQuantity = resource.Quantity{}
var zeroQty = resource.MustParse("0")
func allZeroQty() corev1.ResourceList {
return corev1.ResourceList{
corev1.ResourceCPU: zeroQty,
corev1.ResourceMemory: zeroQty,
corev1.ResourceEphemeralStorage: zeroQty,
}
}
func resolveResourceRequests(containers []corev1.Container, limitRangeMin corev1.ResourceList) []corev1.Container {
max := allZeroQty()
resourceNames := []corev1.ResourceName{corev1.ResourceCPU, corev1.ResourceMemory, corev1.ResourceEphemeralStorage}
maxIndicesByResource := make(map[corev1.ResourceName]int, len(resourceNames))
for _, resourceName := range resourceNames {
maxIndicesByResource[resourceName] = -1
}
// Find max resource requests and associated list indices for
// containers for CPU, memory, and ephemeral storage resources
for i, c := range containers {
for k, v := range c.Resources.Requests {
if v.Cmp(max[k]) > 0 {
maxIndicesByResource[k] = i
max[k] = v
}
}
}
// Use zeroQty if request value is not set for min
if limitRangeMin[corev1.ResourceCPU] == emptyResourceQuantity {
limitRangeMin[corev1.ResourceCPU] = zeroQty
}
if limitRangeMin[corev1.ResourceMemory] == emptyResourceQuantity {
limitRangeMin[corev1.ResourceMemory] = zeroQty
}
if limitRangeMin[corev1.ResourceEphemeralStorage] == emptyResourceQuantity {
limitRangeMin[corev1.ResourceEphemeralStorage] = zeroQty
}
// Set all non max resource requests to 0. Leave max request at index
// originally defined to account for limit of step.
for i := range containers {
if containers[i].Resources.Requests == nil {
containers[i].Resources.Requests = limitRangeMin
continue
}
for _, resourceName := range resourceNames {
if maxIndicesByResource[resourceName] != i {
containers[i].Resources.Requests[resourceName] = limitRangeMin[resourceName]
}
}
}
return containers
}