Implicit call() for models/layers not working

[tatianacv]

Bug in processing the call for call(...) when calling the model (line 36)

ML/com.ibm.wala.cast.python.test/data/tf2_test_model_call2.py

Lines 6 to 36 in eec6f81

	class SequentialModel(tf.keras.Model):
	def __init__(self, **kwargs):
	super(SequentialModel, self).__init__(**kwargs)
	self.flatten = tf.keras.layers.Flatten(input_shape=(28, 28))
	# Add a lot of small layers
	num_layers = 100
	self.my_layers = [tf.keras.layers.Dense(64, activation="relu")
	for n in range(num_layers)]
	self.dropout = tf.keras.layers.Dropout(0.2)
	self.dense_2 = tf.keras.layers.Dense(10)
	def call(self, x):
	x = self.flatten(x)
	for layer in self.my_layers:
	x = layer(x)
	x = self.dropout(x)
	x = self.dense_2(x)
	return x
	input_data = tf.random.uniform([20, 28, 28])
	model = SequentialModel()
	result = model(input_data)

Similar to #24 for __call__, the call(..) method does not appear in the callgraph.

[khatchad]

Can you change the comment for test 2 to refer to this new issue instead of #24?

[tatianacv]

Can you change the comment for test 2 to refer to this new issue instead of #24?

ponder-lab#59

[khatchad]

Since the super class __call__() calls the subclass' __call__(), this is most likely blocked on #107.