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lua analysis html xss detection
Based on lua-htmlparser
1.Xss semantic analysis 2.Help discover xss attacks
package.path = "./src/?.lua;" .. package.path
local xss_engine = require("xss_engine")
local text =[[
<img src=x onerror=alert(1)>
]]
if xss_engine.is_xss(text) then
print("this is info xss")
else
print("this is info not xss")
end
[root@localhost lua-htmlparser]# luajit test2.lua
this is info xss