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[e] (0) Editorial fixes: mis-xreffing, too many 'when's
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git-svn-id: http://svn.whatwg.org/webapps@3995 340c8d12-0b0e-0410-8428-c7bf67bfef74
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@Hixie
Hixie committed Sep 24, 2009
1 parent 35aafd7 commit 8c8d7ed
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18 changes: 9 additions & 9 deletions index
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Original file line number Diff line number Diff line change
Expand Up @@ -24239,9 +24239,10 @@ interface <dfn>CueRangeCallback</dfn> {
or its vertical dimension is zero) then the method must return the
string "<code title="">data:,</code>". (This is the shortest <code title="">data:</code> URL; it represents the empty string in a <code title="">text/plain</code> resource.)</p>

<p>When the <code title=dom-canvas-toDataURL><a href=#dom-canvas-todataurl>toDataURL(<var title="">type</var>)</a></code> method, when called with one <em>or
more</em> arguments, must return a <code title="">data:</code> URL
containing a representation of the image in the format given by <var title="">type</var>. The possible values are <a href=#mime-type title="MIME
<p>When the <code title=dom-canvas-toDataURL><a href=#dom-canvas-todataurl>toDataURL(<var title="">type</var>)</a></code> method is called with one <em>or
more</em> arguments, it must return a <code title="">data:</code>
URL containing a representation of the image in the format given by
<var title="">type</var>. The possible values are <a href=#mime-type title="MIME
type">MIME types</a> with no parameters, for example
<code>image/png</code>, <code>image/jpeg</code>, or even maybe
<code>image/svg+xml</code> if the implementation actually keeps
Expand Down Expand Up @@ -25032,23 +25033,22 @@ idea from Mihai:

<li>

<p>Let <span>x(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">x<sub>1</sub></var>-<var title="">x<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">x<sub>0</sub></var></span></p>
<p>Let <span title="">x(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">x<sub>1</sub></var>-<var title="">x<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">x<sub>0</sub></var></span></p>

<p>Let <span>y(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">y<sub>1</sub></var>-<var title="">y<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">y<sub>0</sub></var></span></p>
<p>Let <span title="">y(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">y<sub>1</sub></var>-<var title="">y<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">y<sub>0</sub></var></span></p>

<p>Let <span>r(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">r<sub>1</sub></var>-<var title="">r<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">r<sub>0</sub></var></span></p>
<p>Let <span title="">r(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var title="">r<sub>1</sub></var>-<var title="">r<sub>0</sub></var>)<var title="">&omega;</var>&nbsp;+&nbsp;<var title="">r<sub>0</sub></var></span></p>

<p>Let the color at <var title="">&omega;</var> be the color at
that position on the gradient (with the colors coming from the <a href=#interpolation>interpolation and extrapolation</a>
described above).</p>

</li>

<li><p>For all values of <var title="">&omega;</var> where
<span>r(<var title="">&omega;</var>)&nbsp;&gt;&nbsp;0</span>,
<li><p>For all values of <var title="">&omega;</var> where <span title="">r(<var title="">&omega;</var>)&nbsp;&gt;&nbsp;0</span>,
starting with the value of <var title="">&omega;</var> nearest to
positive infinity and ending with the value of <var title="">&omega;</var> nearest to negative infinity, draw the
circumference of the circle with radius <span>r(<var title="">&omega;</var>)</span> at position (<span>x(<var title="">&omega;</var>)</span>, <span>y(<var title="">&omega;</var>)</span>), with the color at <var title="">&omega;</var>, but only painting on the parts of the
circumference of the circle with radius <span title="">r(<var title="">&omega;</var>)</span> at position (<span title="">x(<var title="">&omega;</var>)</span>, <span title="">y(<var title="">&omega;</var>)</span>), with the color at <var title="">&omega;</var>, but only painting on the parts of the
canvas that have not yet been painted on by earlier circles in this
step for this rendering of the gradient.</li>

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27 changes: 15 additions & 12 deletions source
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Original file line number Diff line number Diff line change
Expand Up @@ -26345,10 +26345,10 @@ interface <dfn>CueRangeCallback</dfn> {
title="">text/plain</code> resource.)</p>

<p>When the <code title="dom-canvas-toDataURL">toDataURL(<var
title="">type</var>)</code> method, when called with one <em>or
more</em> arguments, must return a <code title="">data:</code> URL
containing a representation of the image in the format given by <var
title="">type</var>. The possible values are <span title="MIME
title="">type</var>)</code> method is called with one <em>or
more</em> arguments, it must return a <code title="">data:</code>
URL containing a representation of the image in the format given by
<var title="">type</var>. The possible values are <span title="MIME
type">MIME types</span> with no parameters, for example
<code>image/png</code>, <code>image/jpeg</code>, or even maybe
<code>image/svg+xml</code> if the implementation actually keeps
Expand Down Expand Up @@ -27271,19 +27271,22 @@ idea from Mihai:

<li>

<p>Let <span>x(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var
<p>Let <span title="">x(<var
title="">&omega;</var>)&nbsp;=&nbsp;(<var
title="">x<sub>1</sub></var>-<var
title="">x<sub>0</sub></var>)<var
title="">&omega;</var>&nbsp;+&nbsp;<var
title="">x<sub>0</sub></var></span></p>

<p>Let <span>y(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var
<p>Let <span title="">y(<var
title="">&omega;</var>)&nbsp;=&nbsp;(<var
title="">y<sub>1</sub></var>-<var
title="">y<sub>0</sub></var>)<var
title="">&omega;</var>&nbsp;+&nbsp;<var
title="">y<sub>0</sub></var></span></p>

<p>Let <span>r(<var title="">&omega;</var>)&nbsp;=&nbsp;(<var
<p>Let <span title="">r(<var
title="">&omega;</var>)&nbsp;=&nbsp;(<var
title="">r<sub>1</sub></var>-<var
title="">r<sub>0</sub></var>)<var
title="">&omega;</var>&nbsp;+&nbsp;<var
Expand All @@ -27296,14 +27299,14 @@ idea from Mihai:

</li>

<li><p>For all values of <var title="">&omega;</var> where
<span>r(<var title="">&omega;</var>)&nbsp;&gt;&nbsp;0</span>,
<li><p>For all values of <var title="">&omega;</var> where <span
title="">r(<var title="">&omega;</var>)&nbsp;&gt;&nbsp;0</span>,
starting with the value of <var title="">&omega;</var> nearest to
positive infinity and ending with the value of <var
title="">&omega;</var> nearest to negative infinity, draw the
circumference of the circle with radius <span>r(<var
title="">&omega;</var>)</span> at position (<span>x(<var
title="">&omega;</var>)</span>, <span>y(<var
circumference of the circle with radius <span title="">r(<var
title="">&omega;</var>)</span> at position (<span title="">x(<var
title="">&omega;</var>)</span>, <span title="">y(<var
title="">&omega;</var>)</span>), with the color at <var
title="">&omega;</var>, but only painting on the parts of the
canvas that have not yet been painted on by earlier circles in this
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