Question about ray direction

[zhshi0816]

Hi,

Thanks for making a great contribution to our PyTorch community. I have a question about the ray direction. The camera projection formulation is as follows:
$u=\frac{x}{z}f+\frac{W}{2},v=-\frac{y}{z}f+\frac{H}{2}$

I just reverse the formulation to derive the ray direction as follows:
$[\frac{u-\frac{W}{2}}{f}z,-\frac{v-\frac{H}{2}}{f}z,z]$.

Then I set z=-1, which is different from your result.
Can anyone show me where I was wrong? How do you calculate the direction?

[JunjieLl]

so have you ever figure out why? I have the same question as yours, would you please give me some response, thanks.

[JunjieLl]

world coordinates $P=(X,Y,Z)$, imaging plane coordinates $P^{{}^{\prime }}=(X^{{}^{\prime }},Y^{{}^{\prime }},Z^{{}^{\prime }})$, pixel coordinates $(u,v)$

$$\frac{Z}{f}=-\frac{X}{X^{{}^{\prime }}}=-\frac{Y}{Y^{{}^{\prime }}}$$

$$X^{{}^{\prime }}=-f\frac{X}{Z},Y^{{}^{\prime }}=-f\frac{Y}{Z}$$

$$u=X^{{}^{\prime }}+c_x,v=Y^{{}^{\prime }}+c_y$$

$$u=-f\frac{X}{Z}+c_x,v=-f\frac{Y}{Z}+c_y$$

$$X=\frac{c_x-u}{f}Z,Y=\frac{c_y-v}{f}Z$$

$$P=(\frac{c_x-u}{f}Z,\frac{c_y-v}{f}Z,Z)$$

$$P=(\frac{u-c_x}{f},\frac{v-c_y}{f},-1),whereZ=-1$$

Finally, I resolve this issue from here, the axis y is reversed and then the equation matches the code.

[chzhan]

世界坐标磷=(X,和,和)，成像平面坐标磷′=(X′,和′,和′)，像素坐标(在,在)

和F=−XX′=−和和′

X′=−FX和,和′=−F和和

在=X′+CX,在=和′+C和

在=−FX和+CX,在=−F和和+C和

X=CX−在F和,和=C和−在F和

磷=(CX−在F和,C和−在F和,和)

磷=(在−CXF,在−C和F,−1), 在H这是r这是 和=−1

最后，我从这里解决了这个问题，y轴反转，然后方程与代码匹配。

遇到了同样的问题，感觉你的推理是对的，但是坐标轴是对不上的，我查了下常用的坐标系，像素坐标系x轴和相机坐标系x轴是同向的，y轴是反方向的