Python-If-Else -> HackerRank Solution

Given an integer, , perform the following conditional actions:

If n is odd, print Weird If n is even and in the inclusive range of 2 to 5, print Not Weird If n is even and in the inclusive range of 6 to 20, print Weird If n is even and greater than 20, print Not Weird Input Format

A single line containing a positive integer, n. Constraints 1<=n<=100 Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0 3 Sample Output 0 Weird Explanation 0 n=3 n is odd and odd numbers are weird, so print Weird.

Sample Input 1 24 Sample Output 1 Not Weird Explanation 1 n=24 n>20 and is even, so it is not weird.

Sol:

x = int(input())
if x%2!=0:
    print('Weird')
else:
    if x>=2 and x<=5:
        print('Not Weird')
    if x>=6 and x<=20:
        print('Weird')
    if x>20:
        print('Not Weird')