Cursed C++

Ever wanted to write C++ with pythonic syntax?

Motivation

I was bored, had nothing better to do. In short:

'motivation' is None

Usage

As a module

You can use this like a regular python module, e.g.

import cursed_cpp

uncursed_code = cursed_cpp.uncurse('code goes here')

As a standalone application

Without arguments

If you run the code as a script without any arguments, the content of the clipboard will be uncursed and set as the new clipboard content. Note that this requires the python library clipboard to be installed.

With a single filename argument

When a single filename argument is specified, the program will uncurse that file's content and put it in a new file in the same directory named uncursed_filename.cpp.

With 2 filename arguments

When 2 filename arguments are specified, the program will uncurse the content of the file in the first filename argument, then put it in a new file in the same directory named as the second filename argument.

What It Does

You can omit the curly braces and semicolons in C++ and instead use indentation similar to Python, e.g.

#include <iostream>
using namespace std;

int main()
{
  
    int x = 0;
  
    for (int i = 0; i < n; i++)
    {
        x += 1;
    }
  
    return 0;
}

can be rewritten as:

#include <iostream>
using namespace std

int main()
  
    int x = 0
  
    for (int i = 0; i < n; i++)
        x += 1
  
    return 0

Notice how there is no : at the end of the for loop unlike Python, this is because I see them as redundant.

The parentheses in if, else if, for and while statements can be omitted if desired. So the above code can further be reduced to:

#include <iostream>
using namespace std

int main()
  
    int x = 0
  
    for int i = 0; i < n; i++
        x += 1
  
    return 0

However, this is not recommended as it usually makes code less readable, but there's always the option to leave the first parenthesis and omit only the second parenthesis ;)

#include <iostream>
using namespace std

int main()
  
    int x = 0
  
    for (int i = 0; i < n; i++
        x += 1
  
    return 0