[HoonDongKang] WEEK 01 solutions #1160
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b41-41
approved these changes
Apr 4, 2025
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| function containsDuplicate(nums: number[]): boolean { | ||
| // 시간복잡도: O(n^2) |
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풀이 별로 함수 분리, 알고리즘 복잡도 주석 설명
위 두 가지 부분이 너무 좋다고 느꼈습니다!!
정리가 잘 되어 있어서 코드를 읽기도 쉬웠고,
나중에 다시 볼 때도 좋은 방식이라고 느낍니다.
저도 다음부터는 이렇게 정리하면 좋겠다고 느꼈고,
깔끔하게 작성하는 것에 대해서 좋은 공부가 되었습니다.
감사합니다!
| function differenceMap(nums: number[], target: number): number[] { | ||
| const diffMap = new Map<number, number>(); | ||
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| for (let [i, num] of nums.entries()) { |
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entries를 사용해서 for문 돌리는 방법도 있었네요.
풀이 방법을 보면서 많이 공부가 되었습니다..!
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