[suwi] Week 05 #866
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[suwi] Week 05 #866
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EgonD3V
approved these changes
Jan 12, 2025
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+26
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| anagrams = defaultdict(list) | ||
| for s in strs: | ||
| sorted_s = "".join(sorted(s)) | ||
| if sorted_s in anagrams: | ||
| anagrams[sorted_s].append(s) | ||
| else: | ||
| anagrams[sorted_s] = [s] |
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Suggested change
| anagrams = defaultdict(list) | |
| for s in strs: | |
| sorted_s = "".join(sorted(s)) | |
| if sorted_s in anagrams: | |
| anagrams[sorted_s].append(s) | |
| else: | |
| anagrams[sorted_s] = [s] | |
| anagrams = {} | |
| for s in strs: | |
| sorted_s = "".join(sorted(s)) | |
| anagrams[sorted_s] = anagrams.get(sorted_s, []) + [s] |
defaultdict를 안쓰고 dict의 내장 메서드를 쓰는 방법도 있어 공유드립니다
| class Trie: | ||
|
|
||
| def __init__(self): | ||
| self.root = {"ending":True} |
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"ending"같은 문자열을 고정적으로 사용한다면 클래스 변수로 선언하여 상수로 사용하는 편이 좋을 것 같습니다
| """ | ||
|
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||
| class Solution: | ||
| def wordBreak(self, s: str, wordDict: List[str]) -> bool: |
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사실 이 문제는 위의 implement-trie-prefix-tree와 연계되는 문제여서 적용한 풀이법을 고민해보시면 좋을 것 같습니다
|
문제마다 주석을 꼼꼼하게 달아주셔서 리뷰하면서 한번 더 공부할 수 있었어요! 이번 주도 고생 많으셨습니다. 다음 주차도 화이팅이에요👏 |
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