Skip to content
forked from ruicore/python

Summary of Python Programming Skills

License

Notifications You must be signed in to change notification settings

Rishi-saw/python-2

 
 

Repository files navigation

Python 使用技巧

This repositorie contains ancillary function which code in python3. Use it freely.

Crawl web function may conatain error(s) as the web elements changed.

If you had any idea to improve my code or you find any mistake in my file, please contact me. (Email me at super76rui@icloud.com)

1.在列表,字典,集合中根据条件筛选数据

需求:

  1. 过滤 list 中大于 0 的数:[14, 0, -6, 0, -10, -8, -1, 19, -10, -16]
  1. 筛选出字典中值大于 0 的项目:{0: 9, 1: -3, 2: -8, 3: 6, 4: -4, 5: -4, 6: -7, 7: -8, 8: 7, 9: -3}
  1. 筛选出集合中能被 2 整除的数:{3, 4, 9, 12, 15, 17, 19, 20}
  1. 找到字典中值最小的健值对:prices = {'ACME': 45.23,'AAPL': 612.78,'IBM': 205.55,'HPQ': 37.20,'FB': 10.75}
  1. 对字典排序,首先按照值排序,值相同再按照健排序 6. 对字典的健按照值排序
list_bigger = [x for x in list_nums if x > 0]
dict_bigget = {k: v for k, v in dict_nums.items() if v > 0}
set_two = {x for x in set_nums if not x % 2}

min_pairs = min(zip(prices.values(),prices.keys()))
sorted_pairs = sorted(zip(prices.values(),prices.keys()))
sorted_keys = sorted(prices,prices.get)
# zip 创建的对象只能访问一次

2.命名,统计,字典

需求:在表格中,每一行的信息固定,为了访问某个位置的值,不使用索引

from collections import namedtuple

stuendt = namedtuple("Student", ["name", "age", "sex"])

s1 = stuendt(name="12", age=12, sex="female")
s2 = stuendt(name="12", age=12, sex="male")

需求: 统计 [5, 2, 2, 3, 1, 5, 1, 3, 2, 4] 出现次数最高的 3 的元素,并找到它们的出现次数 统计一个段落中出现次数最高的前 3 个元素,并确定次数

import re
from collections import Counter

nums = [5, 2, 2, 3, 1, 5, 1, 3, 2, 4]

times = Counter(nums)
com = times.most_common(3)

text = """If operators with different priorities are used, consider adding
whitespace around the operators with the lowest priority(ies). Use
your own judgment; however, never use more than one space, and
always have the same amount of whitespace on both sides of a binary
operator."""
times = Counter(re.split(r"\W+",text))
com = times.most_common(3)

需求:根据字典中值的大小,对字典排序

nums = {0: 9, 1: -3, 2: -8, 3: 6, 4: -4, 5: -4, 6: -7, 7: -8, 8: 7, 9: -3}
res = sorted(nums.items(), key=lambda x: x[1])

需求:找到多个字典中的公共键

from functools import reduce

a = {'b': 7, 'f': 3, 'e': 9}
b = {'d': 8, 'b': 2, 'f': 8, 'e': 10, 'g': 6}
c = {'h': 2, 'e': 7, 'b': 11}

res = reduce(lambda x, y: x & y, map(dict.keys, [a, b, c]))

需求:让字典保持有序

from collections import OrderedDict

order = OrderedDict()
for x in sample("abcdefgh", randint(3, 6)):
    order[x] = randint(4,10)

3.字符串

需求:根据多个分隔符,拆分字符串

import re

text = """If\roperators\r\n with\different<<priorities are\vused, consider adding
whitespace around the operators with the lowest priority(ies). Use
your own judgment;;\however, never use more than one space, and
always have}the\\same amount of whitespace on both sides of a binary
operator."""

res = re.split(r"[\r\n\t\v\\}; .<]+",text)

需求:调整文本中的字符串格式,将 07/20/2019 替换成为 2019-07-20

## 使用了正则的捕获组
import re
text = "07/20/2019"

res = re.sub(r"(\d{2})\/(\d{2})\/(\d{4})", r"\3-\1-\2", text)

4.遍历

需求:同时遍历可迭代对象

from itertools import chain

nums1 = [1, 5, 4, 5]
nums2 = [2, 3, 3]
nums3 = [4, 3, 3, 5, 7, 8, 3]

## 并行遍历
for x, y, z in zip(nums1, nums2, nums3):
    print(x, y, z)
## 串行遍历
for x in chain(nums1, nums2, nums3):
    print(x)

5.类

需求:为了确保用户输入正确格式的数,强制用户使用函数进行访问;为了简介,通过 property 自动调用函数,实现「设置属性自动调用函数的效果」

property 为类创建可管理的属性

class Control(object):
    def __init__(self, value):
        self.value = value

    def get_value(self):
        return self.value

    def set_value(self, num: int):
        if not isinstance(num, (int, float)):
            raise ValueError("please enter num")
        self.value = num

    r = property(get_value, set_value)

需求:实现类的比较

from functools import total_ordering
from abc import ABCMeta, abstractmethod

@total_ordering
class Shape(object):

    @abstractmethod
    def area(self):
        pass

    def __lt__(self, obj):
        if not isinstance(obj, Shape):
            raise TypeError("obj is not a shape")
        return self.area() < obj.area()

    def __eq__(self, obj):
        if not isinstance(obj, Shape):
            raise TypeError("obj is not a shape")
        return self.area() == obj.area()

class Cirlcle(Shape):
    def __init__(self, radius):
        self.radius = radius

    def area(self):
        return 3.14*self.radius**2

class Rect(Shape):
    def __init__(self, weight, height):
        self.weight = weight
        self.height = height

    def area(self):
        return self.weight*self.height

cricle = Cirlcle(3)
rect = Rect(3, 4)
print(cricle >= rect)

需求:对实例的类做类型检查

class Attr(object):
    def __init__(self, name, type_):
        self.name = name
        self.type_ = type_


    def __get__(self, instance, cls):
        return instance.__dict__[self.name]


    def __set__(self, instance, value):
        if not isinstance(value, self.type_):
            raise TypeError("expect a {}".format(self.type_))
        instance.__dict__[self.name] = value


    def __delete__(self, instance):
        del instance.__dict__[self.name]


class Monkey(object):
    name = Attr("name", str)
    age = Attr("age", int)
    gender = Attr("gender", str)

需求:根据字符串执行实例的函数

from operator import methodcaller

class MethonCall(object):
    def get_value(self, value: int, value2: int):
        return 12*value*value2

mc = MethonCall()
fun = methodcaller("get_value", 2, -1)
print(fun(mc))

6. 装饰器

  1. 需求:为某一个函数增加功能,不影响原来的函数
from functools import wraps, update_wrapper


def add_cache(fun):
    cache = dict()


    @wraps(fun)
    def handler(*arg):
        if arg not in cache:
            cache[arg] = fun(*arg)
        return cache[arg]
    ## update_wrapper(handler, fun, ("__name__", "__doc__"), ("__dict__",))
    return handler


@add_cache
def fibonacci(n):
    if n <= 1:
        return 1
    return fibonacci(n-1)+fibonacci(n-2)


print(fibonacci(89))
  1. 带参数的装饰器
import time
import logging
from random import randint

def warn(timeout):
    timeout = [timeout]

    def decorator(fun):
        def wrapper(*args, **kwargs):
            start = time.time()
            res = fun(*args, **kwargs)
            end = time.time()
            used = end-start
            if used > timeout[0]:
                logging.warn("{}:{} > {}".format(fun.__name__, used, timeout[0]))
            return res

        def set_timeout(k):
            timeout[0] = k
        wrapper.set_timeout = set_timeout

        return wrapper

    return decorator

@warn(1)
def test():
    print("正在测试")
    while randint(0, 1):
        time.sleep(0.5)

for i in range(20):
    test()

test.set_timeout(1.2)

for i in range(20):
    test()

7. 优先队列

需求:实现一个有优先级的队列

import heapq

class PriorityQueue(object):
    def __init__(self):
        self._queue = []
        self._index = 0

    def push(self, item, priority):
        heapq.heappush(self._queue, (-priority, self._index, item))
        self._index += 1

    def pop(self):
        return heapq.heappop(self._queue)[-1] if self._queue else None

8. 展开嵌套的 list

from collections.abc import Iterable

def flatten(items, ignore_types=(str, bytes)):
    for x in items:
        if isinstance(x, Iterable) and not isinstance(x, ignore_types):
            yield from flatten(x)
        else:
            yield x

items = [1, 2, [3, 4, (5, 6), 7], 8, "temp", "core", {-1, -2, -4, -6}]

for x in flatten(items):
    print(x)

9. 文件

  1. 打印输出到文件中
with open('d:/work/test.txt', 'wt') as f:
    print('Hello World!', file=f)


# 文件必须以文本格式打开
  1. 文件不存在时才能写入
with open('somefile', 'xt') as f:
    f.write('Hello\n')

10. 使用强制关键字参数

def recv(maxsize, *, block):
    'Receives a message'
    pass

recv(1024, True) # TypeError
recv(1024, block=True) # Ok

11. 比较两个字典是否相等

  • 键个数相等,键名一一对应,键值一一对应相等
import json
from datetime import datetime

from bson.json_util import default


def compare_2_dict(dict_1, dict_2):
    return (json.dumps(dict_1, default=default, sort_keys=dict.keys) ==
                json.dumps(dict_2, default=default, sort_keys=dict.keys))


dicta = {"a": datetime.now(), "b": 2}
dictb = {"a": datetime.now(), "b": 2}

print(compare_2_dict(dicta, dictb))

About

Summary of Python Programming Skills

Resources

License

Stars

Watchers

Forks

Releases

No releases published

Packages

No packages published

Languages

  • Python 98.8%
  • Makefile 1.2%