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16 changes: 16 additions & 0 deletions MeetInTheMiddle/README.md
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# Meet in the Middle

## 📘 Overview
**Meet in the Middle** is an optimization technique used for solving problems
that would otherwise take **exponential time (O(2^N))**.
It divides the problem into two halves and combines the results,
reducing complexity to **O(2^(N/2))**, which is much faster.

---

## ⚙️ How It Works
1. **Divide** the input set or problem into two halves.
2. **Generate all possible results** (like subset sums) for each half.
3. **Sort one list** and use **binary search or two-pointer** techniques
to efficiently combine results from both halves.

90 changes: 90 additions & 0 deletions MeetInTheMiddle/subset_sum_meet_in_middle.cpp
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/**
* @file subset_sum_meet_in_middle.cpp
* @brief Count subsets with sum <= target using the Meet in the Middle
* technique.
* @details
* The Meet in the Middle algorithm splits the array into two halves,
* generates all subset sums for each half, then efficiently counts
* valid combinations using binary search.
* @see https://cp-algorithms.com/combinatorics/meet_in_the_middle.html
* @author [Your Name](https://github.com/your-github-handle)
*/

#include <algorithm> ///< for std::sort, std::upper_bound
#include <cassert> ///< for assert()
#include <iostream> ///< for std::cout
#include <vector> ///< for std::vector

/**
* @brief Generates all subset sums for the range arr[start..end]
* @param arr Input array
* @param sums Vector to store generated sums
* @param start Start index
* @param end End index
* @param curr Current sum (default 0)
*/
void generateSubsetSums(const std::vector<int>& arr,
std::vector<long long>& sums, int start, int end,
long long curr = 0) {
if (start > end) {
sums.push_back(curr);
return;
}
generateSubsetSums(arr, sums, start + 1, end,
curr); // Exclude current element
generateSubsetSums(arr, sums, start + 1, end,
curr + arr[start]); // Include current element
}

/**
* @brief Counts subsets with sum <= target using Meet in the Middle
* @param arr Input array
* @param target Maximum allowed sum
* @return Number of subsets with sum <= target
*/
long long countSubsetsMeetInMiddle(const std::vector<int>& arr, int target) {
int n = arr.size();
std::vector<long long> left, right;

// Generate subset sums for left and right halves
generateSubsetSums(arr, left, 0, n / 2 - 1);
generateSubsetSums(arr, right, n / 2, n - 1);

std::sort(right.begin(), right.end());

long long count = 0;
for (auto s : left) {
// Count combinations with sum <= target using binary search
count += std::upper_bound(right.begin(), right.end(), target - s) -
right.begin();
}

return count;
}

/**
* @brief Self-test to verify the implementation
*/
static void tests() {
// Test case 1
std::vector<int> arr1 = {3, 5, 7, 9};
assert(countSubsetsMeetInMiddle(arr1, 12) == 9);

// Test case 2
std::vector<int> arr2 = {1, 2, 3};
assert(countSubsetsMeetInMiddle(arr2, 3) == 5);

// Test case 3
std::vector<int> arr3 = {4, 5, 6, 7};
assert(countSubsetsMeetInMiddle(arr3, 10) == 7);

std::cout << "All self-tests passed successfully!\n";
}

/**
* @brief Main function
*/
int main() {
tests();
return 0;
}