Fix ArrayIndexOutOfBoundException when check bytes in a range [0x80; 0xFF] to be a hex digit #11
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byte
is a signed type and the[]
operator takes anint
as an index.When you index array using
byte
index it is promoted to theint
type. The most significant bit of abyte
(which is a sign bit) promoted to theint
resulting in a negative value. As a resultArrayIndexOutOfBoundException
can be thrown.Using a
& 0xFF
trick is a standard way to prevent sign promotion and treatbyte
as an unsigned value.