Use same description as pulseInLong() for pulseIn() #372
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pulseIn() and pulseInLong() work the same and thus the descriptions should also be the same. - Correct explanation of how the timeout works. The timeout applies to the entire duration of the function call, not only to the start of the pulse. - Consistent formatting.
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pulseIn() and pulseInLong() work the same and thus the descriptions should also be the same. This pull request uses the pulseInLong() description as proposed in #371.
Fixes: arduino/Arduino#7664
CC: @davidje13
References: