app no longer passed in as initial argument in Flask-Script commands

[danjac]

Using latest version of Flask-Script (0.3) I get this error:

Traceback (most recent call last):
File "manage.py", line 155, in
manager.run()
File "//lib/python2.6/site-packages/Flask_Script-0.3-py2.6.egg/flaskext/script.py", line 636, in run
sys.argv[2:])
File "/lib/python2.6/site-packages/Flask_Script-0.3-py2.6.egg/flaskext/script.py", line 618, in handle
command.run(**command_namespace.dict)
TypeError: run() takes exactly 6 non-keyword arguments (1 given)

The run() method of Command no longer takes app as first argument, as of version 0.3 (current release) - this is because the "app" is already available as "current_app" in the Flask request context, so it's superfluous.

This is not entirely clear in the documentation, and I will update the Flask-Script docs regarding this issue.

[coderanger]

Update Flask-Zen to use the new Flask-Script API (no app argument, use flask.current_app instead). Closed by c390be2.