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[...] and, if X is the most derived class ([class.base.init]), its destructor calls the destructors for X's virtual base classes. [...]
When the destructor is implicitly invoked, the structure of objects to be destroy are statically known, and thus it's clear whether every X is the most derived class.
However, if the destructor is explicitly invoked, there can be situations where the structure of the explicitly destroyed object is not statically known. As a result, it may be unclear to the implementation whether destructors need to or not to be called for virtual base class subobjects.
E.g. in the following example, does the explicit destructor invocation call B::~B?
structB {
B() = default;
~B() { /* some operations */ }
};
structDX : virtual B {};
structDY : virtual B {};
structDZ : DX, DY {};
template<classT>
union NoDestroy {
T val;
NoDestroy() : val() {}
NoDestroy(const NoDestroy&) = delete;
NoDestroy &operator=(const NoDestroy&) = delete;
~NoDestroy() {}
};
intmain()
{
NoDestroy<DZ> d{};
static_cast<DY&>(d.val).~DY();
}
It doesn't seem intended to require the implementation to record whether such an object is a most derived object. Current implementations call destructors for virtual base class subobjects whenever the destructor of the derived class is explicitly called. However, on some implementations (GCC and Clang), such an explicit destructor call can be only valid for most derived objects (llvm/llvm-project#74282).