Even though the line println('Cyrill's Computer: Hey hey hey') is written after the line spawner.spawn(...), The 'Cyrill's Computer: Hey hey hey' appears first in the terminal. This is because the spawn function schedules the task to be executed asynchronously, but it does not block the execution of the main thread. Therefore, the println('Cyrill's Computer: Hey hey hey') statement is executed immediately, while the spawned task runs concurrently in the background
drop(spawner) shows that we have finished sending message to the queue and the executor to finish the task in hand and finally end the program. By removing the drop(spawner) the executioner expects other tasks to be spawned.
When spawning multiple tasks, the tasks are done asynchronously, therefore the result in the console are not in the same order.