Typo in HttpClient.findProxyFromEnvironment documentation

[sgrekhov]

Please see HttpClient.findProxyFromEnvironment

If you don't want to use the system environment you can use a different one by wrapping the function.

HttpClient client = new HttpClient();
client.findProxy = (url) {
return HttpClient.findProxyFromEnvironment(
url, {"http_proxy": ..., "no_proxy": ...});
}

The second argument of findProxyFromEnvironment is named, so change the code to:

HttpClient client = new HttpClient();
client.findProxy = (url) {
  return HttpClient.findProxyFromEnvironment(
      url, environment: {"http_proxy": ..., "no_proxy": ...}); 
}