revisit get_package_dir #57
Description
Problem
no problem, but I think we are handling this task differently in other packages so let's revisit and see if there is a standard way to do it. In general, I would rather not have it in the __init__.py file. I am not sure why, but I never really like importing things from there as a I don't fully understand the behavior.
Proposed solution
Right now it has to be there because files(__name) returns the package name when it is called from the init for some reason, and then this is returned as a context manager. I think in other packages in diffpy where we are trying to do the same thing, we do something like find the path of current file as a Pathlib object, then recurse around using .parent and so on to get the path we are after and then pass that to a function that opens the file. This just seems more explicit and less magical to me.