feat: update sql solutions to lc problems

solution/0100-0199/0183.Customers Who Never Order/README.md

@@ -57,22 +57,23 @@
 ### **SQL**
 
 ```sql
-SELECT Name AS Customers
+# Write your MySQL query statement below
+SELECT name AS Customers
 FROM Customers
 WHERE
     id NOT IN (
-        SELECT CustomerId
+        SELECT customerId
         FROM Orders
     );
 ```
 
 ```sql
-SELECT
-    c.Name AS Customers
+# Write your MySQL query statement below
+SELECT name AS Customers
 FROM
-    customers AS c
-    LEFT JOIN orders AS o ON c.Id = o.CustomerId
-WHERE o.CustomerId IS NULL;
+    Customers AS c
+    LEFT JOIN Orders AS o ON c.id = o.customerId
+WHERE o.id IS NULL;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0183.Customers Who Never Order/README_EN.md

@@ -78,22 +78,23 @@ Orders table:
 ### **SQL**
 
 ```sql
-SELECT Name AS Customers
+# Write your MySQL query statement below
+SELECT name AS Customers
 FROM Customers
 WHERE
     id NOT IN (
-        SELECT CustomerId
+        SELECT customerId
         FROM Orders
     );
 ```
 
 ```sql
-SELECT
-    c.Name AS Customers
+# Write your MySQL query statement below
+SELECT name AS Customers
 FROM
-    customers AS c
-    LEFT JOIN orders AS o ON c.Id = o.CustomerId
-WHERE o.CustomerId IS NULL;
+    Customers AS c
+    LEFT JOIN Orders AS o ON c.id = o.customerId
+WHERE o.id IS NULL;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0183.Customers Who Never Order/Solution.sql

@@ -1,7 +1,8 @@
-SELECT Name AS Customers
+# Write your MySQL query statement below
+SELECT name AS Customers
 FROM Customers
 WHERE
     id NOT IN (
-        SELECT CustomerId
+        SELECT customerId
         FROM Orders
     );

solution/0100-0199/0184.Department Highest Salary/README.md

@@ -122,23 +122,18 @@ WHERE
 ```sql
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
 WHERE rk = 1;
 ```

solution/0100-0199/0184.Department Highest Salary/README_EN.md

@@ -120,23 +120,18 @@ WHERE
 ```sql
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
 WHERE rk = 1;
 ```

solution/0100-0199/0184.Department Highest Salary/Solution.sql

@@ -1,21 +1,16 @@
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
 WHERE rk = 1;

solution/0100-0199/0185.Department Top Three Salaries/README.md

@@ -125,25 +125,20 @@ WHERE
 ```sql
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             dense_rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
-WHERE rk < 4;
+WHERE rk <= 3;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0185.Department Top Three Salaries/README_EN.md

@@ -121,25 +121,20 @@ WHERE
 ```sql
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             dense_rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
-WHERE rk < 4;
+WHERE rk <= 3;
 ```
 
 <!-- tabs:end -->

solution/0100-0199/0185.Department Top Three Salaries/Solution.sql

@@ -1,21 +1,16 @@
 # Write your MySQL query statement below
 WITH
-    t AS (
+    T AS (
         SELECT
-            departmentId,
-            name,
-            salary,
+            *,
             dense_rank() OVER (
                 PARTITION BY departmentId
                 ORDER BY salary DESC
             ) AS rk
         FROM Employee
     )
-SELECT
-    d.name AS Department,
-    t.name AS Employee,
-    salary AS Salary
+SELECT d.name AS Department, t.name AS Employee, salary AS Salary
 FROM
-    t
+    T AS t
     JOIN Department AS d ON t.departmentId = d.id
-WHERE rk < 4;
+WHERE rk <= 3;

solution/0100-0199/0196.Delete Duplicate Emails/README.md

@@ -61,13 +61,29 @@ Person 表:
 ### **SQL**
 
 ```sql
+# Write your MySQL query statement below
 DELETE FROM Person
 WHERE
-    Id NOT IN (
-        SELECT
-            MIN(Id)
-        FROM (SELECT * FROM Person) AS p
-        GROUP BY p.Email
+    id NOT IN (SELECT min(id) FROM (SELECT * FROM Person) AS p GROUP BY email);
+```
+
+```sql
+# Write your MySQL query statement below
+DELETE FROM Person
+WHERE
+    id NOT IN (
+        SELECT id
+        FROM
+            (
+                SELECT
+                    id,
+                    row_number() OVER (
+                        PARTITION BY email
+                        ORDER BY id
+                    ) AS rk
+                FROM Person
+            ) AS p
+        WHERE rk = 1
     );
 ```
 

solution/0100-0199/0196.Delete Duplicate Emails/README_EN.md

@@ -55,13 +55,29 @@ Person table:
 ### **SQL**
 
 ```sql
+# Write your MySQL query statement below
 DELETE FROM Person
 WHERE
-    Id NOT IN (
-        SELECT
-            MIN(Id)
-        FROM (SELECT * FROM Person) AS p
-        GROUP BY p.Email
+    id NOT IN (SELECT min(id) FROM (SELECT * FROM Person) AS p GROUP BY email);
+```
+
+```sql
+# Write your MySQL query statement below
+DELETE FROM Person
+WHERE
+    id NOT IN (
+        SELECT id
+        FROM
+            (
+                SELECT
+                    id,
+                    row_number() OVER (
+                        PARTITION BY email
+                        ORDER BY id
+                    ) AS rk
+                FROM Person
+            ) AS p
+        WHERE rk = 1
     );
 ```
 

solution/0100-0199/0196.Delete Duplicate Emails/Solution.sql

@@ -1,8 +1,4 @@
+# Write your MySQL query statement below
 DELETE FROM Person
 WHERE
-    Id NOT IN (
-        SELECT
-            MIN(Id)
-        FROM (SELECT * FROM Person) AS p
-        GROUP BY p.Email
-    );
+    id NOT IN (SELECT min(id) FROM (SELECT * FROM Person) AS p GROUP BY email);

solution/0100-0199/0197.Rising Temperature/README.md

@@ -66,13 +66,13 @@ Weather 表：</code>
 ### **SQL**
 
 ```sql
-SELECT w1.Id
+# Write your MySQL query statement below
+SELECT w1.id
 FROM
-    Weather AS w1,
-    Weather AS w2
-WHERE
-    DATEDIFF(w1.RecordDate, w2.RecordDate) = 1
-    AND w1.Temperature > w2.Temperature;
+    Weather AS w1
+    JOIN Weather AS w2
+        ON datediff(w1.recordDate, w2.recordDate) = 1
+        AND w1.temperature > w2.temperature;
 ```
 
 ```sql

solution/0100-0199/0197.Rising Temperature/README_EN.md

@@ -59,13 +59,13 @@ In 2015-01-04, the temperature was higher than the previous day (20 -> 30).
 ### **SQL**
 
 ```sql
-SELECT w1.Id
+# Write your MySQL query statement below
+SELECT w1.id
 FROM
-    Weather AS w1,
-    Weather AS w2
-WHERE
-    DATEDIFF(w1.RecordDate, w2.RecordDate) = 1
-    AND w1.Temperature > w2.Temperature;
+    Weather AS w1
+    JOIN Weather AS w2
+        ON datediff(w1.recordDate, w2.recordDate) = 1
+        AND w1.temperature > w2.temperature;
 ```
 
 ```sql

solution/0100-0199/0197.Rising Temperature/Solution.sql

@@ -1,7 +1,7 @@
-SELECT w1.Id
+# Write your MySQL query statement below
+SELECT w1.id
 FROM
-    Weather AS w1,
-    Weather AS w2
-WHERE
-    DATEDIFF(w1.RecordDate, w2.RecordDate) = 1
-    AND w1.Temperature > w2.Temperature;
+    Weather AS w1
+    JOIN Weather AS w2
+        ON datediff(w1.recordDate, w2.recordDate) = 1
+        AND w1.temperature > w2.temperature;