feat: add sql solutions to lc problems: No.0550,0570

.github/pull_request_template.md

@@ -3,12 +3,14 @@
 <!--
 Below are template for copilot to generate CR message.
 Please DO NOT modify it.
--->
+
 
 ### Description
 
 copilot:summary
 
 ### Explanation of Changes
 
-copilot:walkthrough
+copilot:walkthrough
+
+-->

.prettierrc

@@ -13,6 +13,7 @@
     "overrides": [
         {
             "files": [
+                "solution/0500-0599/0550.Game Play Analysis IV/Solution.sql",
                 "solution/0500-0599/0578.Get Highest Answer Rate Question/Solution.sql",
                 "solution/0600-0699/0610.Triangle Judgement/Solution.sql",
                 "solution/0600-0699/0618.Students Report By Geography/Solution.sql",

solution/0500-0599/0550.Game Play Analysis IV/README.md

@@ -71,4 +71,34 @@ FROM
         AND DATEDIFF(a.event_date, b.event_date) = -1;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            player_id,
+            datediff(
+                lead(event_date) OVER (
+                    PARTITION BY player_id
+                    ORDER BY event_date
+                ),
+                event_date
+            ) AS diff,
+            row_number() OVER (
+                PARTITION BY player_id
+                ORDER BY event_date
+            ) AS rk
+        FROM Activity
+    )
+SELECT
+    round(
+        count(DISTINCT if(diff = 1, player_id, NULL)) / count(
+            DISTINCT player_id
+        ),
+        2
+    ) AS fraction
+FROM T
+WHERE rk = 1;
+```
+
 <!-- tabs:end -->

solution/0500-0599/0550.Game Play Analysis IV/README_EN.md

@@ -73,4 +73,34 @@ FROM
         AND DATEDIFF(a.event_date, b.event_date) = -1;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            player_id,
+            datediff(
+                lead(event_date) OVER (
+                    PARTITION BY player_id
+                    ORDER BY event_date
+                ),
+                event_date
+            ) AS diff,
+            row_number() OVER (
+                PARTITION BY player_id
+                ORDER BY event_date
+            ) AS rk
+        FROM Activity
+    )
+SELECT
+    round(
+        count(DISTINCT if(diff = 1, player_id, NULL)) / count(
+            DISTINCT player_id
+        ),
+        2
+    ) AS fraction
+FROM T
+WHERE rk = 1;
+```
+
 <!-- tabs:end -->

solution/0500-0599/0570.Managers with at Least 5 Direct Reports/README.md

@@ -80,4 +80,20 @@ FROM
         ON e1.id = e2.managerId;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            managerId,
+            count(1) OVER (PARTITION BY managerId) AS cnt
+        FROM Employee
+    )
+SELECT DISTINCT name
+FROM
+    Employee AS e
+    JOIN T AS t ON e.id = t.managerId
+WHERE cnt >= 5;
+```
+
 <!-- tabs:end -->

solution/0500-0599/0570.Managers with at Least 5 Direct Reports/README_EN.md

@@ -76,4 +76,20 @@ FROM
         ON e1.id = e2.managerId;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            managerId,
+            count(1) OVER (PARTITION BY managerId) AS cnt
+        FROM Employee
+    )
+SELECT DISTINCT name
+FROM
+    Employee AS e
+    JOIN T AS t ON e.id = t.managerId
+WHERE cnt >= 5;
+```
+
 <!-- tabs:end -->

solution/0500-0599/0570.Managers with at Least 5 Direct Reports/Solution.sql

@@ -1,14 +1,13 @@
 # Write your MySQL query statement below
-SELECT
-    name
-FROM
-    Employee AS e1
-    JOIN (
+WITH
+    T AS (
         SELECT
-            managerId
+            managerId,
+            count(1) OVER (PARTITION BY managerId) AS cnt
         FROM Employee
-        WHERE managerId IS NOT NULL
-        GROUP BY managerId
-        HAVING count(1) >= 5
-    ) AS e2
-        ON e1.id = e2.managerId;
+    )
+SELECT DISTINCT name
+FROM
+    Employee AS e
+    JOIN T AS t ON e.id = t.managerId
+WHERE cnt >= 5;