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97 changes: 97 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/README.md
Original file line number Diff line number Diff line change
Expand Up @@ -93,22 +93,119 @@ false

<!-- 这里可写通用的实现逻辑 -->

**方法一:遍历检查**

我们观察发现,只要不满足 $words[i][j] = words[j][i]$,就可以直接返回 `false`。

因此,我们只需要遍历每一行,然后检查每一行是否满足 $words[i][j] = words[j][i]$ 即可。注意,如果下标越界,也直接返回 `false`。

时间复杂度 $O(n^2)$,其中 $n$ 是 $words$ 的长度。空间复杂度 $O(1)$。

<!-- tabs:start -->

### **Python3**

<!-- 这里可写当前语言的特殊实现逻辑 -->

```python
class Solution:
def validWordSquare(self, words: List[str]) -> bool:
m = len(words)
n = max(len(w) for w in words)
if m != n:
return False
for j in range(n):
if words[j] != "".join(w[j] for w in words if j < len(w)):
return False
return True
```

```python
class Solution:
def validWordSquare(self, words: List[str]) -> bool:
m = len(words)
for i, w in enumerate(words):
for j, c in enumerate(w):
if j >= m or i >= len(words[j]) or c != words[j][i]:
return False
return True
```

### **Java**

<!-- 这里可写当前语言的特殊实现逻辑 -->

```java
class Solution {
public boolean validWordSquare(List<String> words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words.get(i).length();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words.get(j).length()) {
return false;
}
if (words.get(i).charAt(j) != words.get(j).charAt(i)) {
return false;
}
}
}
return true;
}
}
```

### **C++**

```cpp
class Solution {
public:
bool validWordSquare(vector<string>& words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words[i].size();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words[j].size() || words[i][j] != words[j][i]) {
return false;
}
}
}
return true;
}
};
```

### **Go**

```go
func validWordSquare(words []string) bool {
m := len(words)
for i, w := range words {
for j := range w {
if j >= m || i >= len(words[j]) || w[j] != words[j][i] {
return false
}
}
}
return true
}
```

### **TypeScript**

```ts
function validWordSquare(words: string[]): boolean {
const m = words.length;
for (let i = 0; i < m; ++i) {
const n = words[i].length;
for (let j = 0; j < n; ++j) {
if (j >= m || i >= words[j].length || words[i][j] !== words[j][i]) {
return false;
}
}
}
return true;
}
```

### **...**
Expand Down
89 changes: 89 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/README_EN.md
Original file line number Diff line number Diff line change
Expand Up @@ -61,13 +61,102 @@ Therefore, it is NOT a valid word square.
### **Python3**

```python
class Solution:
def validWordSquare(self, words: List[str]) -> bool:
m = len(words)
n = max(len(w) for w in words)
if m != n:
return False
for j in range(n):
if words[j] != "".join(w[j] for w in words if j < len(w)):
return False
return True
```

```python
class Solution:
def validWordSquare(self, words: List[str]) -> bool:
m = len(words)
for i, w in enumerate(words):
for j, c in enumerate(w):
if j >= m or i >= len(words[j]) or c != words[j][i]:
return False
return True
```

### **Java**

```java
class Solution {
public boolean validWordSquare(List<String> words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words.get(i).length();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words.get(j).length()) {
return false;
}
if (words.get(i).charAt(j) != words.get(j).charAt(i)) {
return false;
}
}
}
return true;
}
}
```

### **C++**

```cpp
class Solution {
public:
bool validWordSquare(vector<string>& words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words[i].size();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words[j].size() || words[i][j] != words[j][i]) {
return false;
}
}
}
return true;
}
};
```

### **Go**

```go
func validWordSquare(words []string) bool {
m := len(words)
for i, w := range words {
for j := range w {
if j >= m || i >= len(words[j]) || w[j] != words[j][i] {
return false
}
}
}
return true
}
```

### **TypeScript**

```ts
function validWordSquare(words: string[]): boolean {
const m = words.length;
for (let i = 0; i < m; ++i) {
const n = words[i].length;
for (let j = 0; j < n; ++j) {
if (j >= m || i >= words[j].length || words[i][j] !== words[j][i]) {
return false;
}
}
}
return true;
}
```

### **...**
Expand Down
15 changes: 15 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/Solution.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,15 @@
class Solution {
public:
bool validWordSquare(vector<string>& words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words[i].size();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words[j].size() || words[i][j] != words[j][i]) {
return false;
}
}
}
return true;
}
};
11 changes: 11 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/Solution.go
Original file line number Diff line number Diff line change
@@ -0,0 +1,11 @@
func validWordSquare(words []string) bool {
m := len(words)
for i, w := range words {
for j := range w {
if j >= m || i >= len(words[j]) || w[j] != words[j][i] {
return false
}
}
}
return true
}
17 changes: 17 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/Solution.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
class Solution {
public boolean validWordSquare(List<String> words) {
int m = words.size();
for (int i = 0; i < m; ++i) {
int n = words.get(i).length();
for (int j = 0; j < n; ++j) {
if (j >= m || i >= words.get(j).length()) {
return false;
}
if (words.get(i).charAt(j) != words.get(j).charAt(i)) {
return false;
}
}
}
return true;
}
}
8 changes: 8 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/Solution.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,8 @@
class Solution:
def validWordSquare(self, words: List[str]) -> bool:
m = len(words)
for i, w in enumerate(words):
for j, c in enumerate(w):
if j >= m or i >= len(words[j]) or c != words[j][i]:
return False
return True
12 changes: 12 additions & 0 deletions solution/0400-0499/0422.Valid Word Square/Solution.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
function validWordSquare(words: string[]): boolean {
const m = words.length;
for (let i = 0; i < m; ++i) {
const n = words[i].length;
for (let j = 0; j < n; ++j) {
if (j >= m || i >= words[j].length || words[i][j] !== words[j][i]) {
return false;
}
}
}
return true;
}