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Mar 31, 2024
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feat: add solutions to lc problems: No.3095,3097 #2522

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132 changes: 128 additions & 4 deletions solution/3000-3099/3095.Shortest Subarray With OR at Least K I/README.md
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Original file line number Diff line number Diff line change
Expand Up @@ -64,24 +64,148 @@

## 解法

### 方法一
### 方法一：双指针 + 计数

<!-- tabs:start -->

```python

class Solution:
def minimumSubarrayLength(self, nums: List[int], k: int) -> int:
n = len(nums)
cnt = [0] * 32
ans = n + 1
s = i = 0
for j, x in enumerate(nums):
s |= x
for h in range(32):
if x >> h & 1:
cnt[h] += 1
while s >= k and i <= j:
ans = min(ans, j - i + 1)
y = nums[i]
for h in range(32):
if y >> h & 1:
cnt[h] -= 1
if cnt[h] == 0:
s ^= 1 << h
i += 1
return -1 if ans > n else ans
```

```java

class Solution {
public int minimumSubarrayLength(int[] nums, int k) {
int n = nums.length;
int[] cnt = new int[32];
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = Math.min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
}
```

```cpp

class Solution {
public:
int minimumSubarrayLength(vector<int>& nums, int k) {
int n = nums.size();
int cnt[32]{};
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
};
```

```go
func minimumSubarrayLength(nums []int, k int) int {
n := len(nums)
cnt := [32]int{}
ans := n + 1
s, i := 0, 0
for j, x := range nums {
s |= x
for h := 0; h < 32; h++ {
if x>>h&1 == 1 {
cnt[h]++
}
}
for ; s >= k && i <= j; i++ {
ans = min(ans, j-i+1)
for h := 0; h < 32; h++ {
if nums[i]>>h&1 == 1 {
cnt[h]--
if cnt[h] == 0 {
s ^= 1 << h
}
}
}
}
}
if ans == n+1 {
return -1
}
return ans
}
```

```ts
function minimumSubarrayLength(nums: number[], k: number): number {
const n = nums.length;
let ans = n + 1;
const cnt: number[] = new Array<number>(32).fill(0);
for (let i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (let h = 0; h < 32; ++h) {
if (((nums[j] >> h) & 1) === 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = Math.min(ans, j - i + 1);
for (let h = 0; h < 32; ++h) {
if (((nums[i] >> h) & 1) === 1 && --cnt[h] === 0) {
s ^= 1 << h;
}
}
}
}
return ans === n + 1 ? -1 : ans;
}
```

<!-- tabs:end -->
Expand Down
130 changes: 127 additions & 3 deletions solution/3000-3099/3095.Shortest Subarray With OR at Least K I/README_EN.md
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Original file line number Diff line number Diff line change
Expand Up @@ -65,19 +65,143 @@
<!-- tabs:start -->

```python

class Solution:
def minimumSubarrayLength(self, nums: List[int], k: int) -> int:
n = len(nums)
cnt = [0] * 32
ans = n + 1
s = i = 0
for j, x in enumerate(nums):
s |= x
for h in range(32):
if x >> h & 1:
cnt[h] += 1
while s >= k and i <= j:
ans = min(ans, j - i + 1)
y = nums[i]
for h in range(32):
if y >> h & 1:
cnt[h] -= 1
if cnt[h] == 0:
s ^= 1 << h
i += 1
return -1 if ans > n else ans
```

```java

class Solution {
public int minimumSubarrayLength(int[] nums, int k) {
int n = nums.length;
int[] cnt = new int[32];
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = Math.min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
}
```

```cpp

class Solution {
public:
int minimumSubarrayLength(vector<int>& nums, int k) {
int n = nums.size();
int cnt[32]{};
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
};
```

```go
func minimumSubarrayLength(nums []int, k int) int {
n := len(nums)
cnt := [32]int{}
ans := n + 1
s, i := 0, 0
for j, x := range nums {
s |= x
for h := 0; h < 32; h++ {
if x>>h&1 == 1 {
cnt[h]++
}
}
for ; s >= k && i <= j; i++ {
ans = min(ans, j-i+1)
for h := 0; h < 32; h++ {
if nums[i]>>h&1 == 1 {
cnt[h]--
if cnt[h] == 0 {
s ^= 1 << h
}
}
}
}
}
if ans == n+1 {
return -1
}
return ans
}
```

```ts
function minimumSubarrayLength(nums: number[], k: number): number {
const n = nums.length;
let ans = n + 1;
const cnt: number[] = new Array<number>(32).fill(0);
for (let i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (let h = 0; h < 32; ++h) {
if (((nums[j] >> h) & 1) === 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = Math.min(ans, j - i + 1);
for (let h = 0; h < 32; ++h) {
if (((nums[i] >> h) & 1) === 1 && --cnt[h] === 0) {
s ^= 1 << h;
}
}
}
}
return ans === n + 1 ? -1 : ans;
}
```

<!-- tabs:end -->
Expand Down
27 changes: 27 additions & 0 deletions solution/3000-3099/3095.Shortest Subarray With OR at Least K I/Solution.cpp
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Original file line number Diff line number Diff line change
@@ -0,0 +1,27 @@
class Solution {
public:
int minimumSubarrayLength(vector<int>& nums, int k) {
int n = nums.size();
int cnt[32]{};
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
};
29 changes: 29 additions & 0 deletions solution/3000-3099/3095.Shortest Subarray With OR at Least K I/Solution.go
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Open in desktop
Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
func minimumSubarrayLength(nums []int, k int) int {
n := len(nums)
cnt := [32]int{}
ans := n + 1
s, i := 0, 0
for j, x := range nums {
s |= x
for h := 0; h < 32; h++ {
if x>>h&1 == 1 {
cnt[h]++
}
}
for ; s >= k && i <= j; i++ {
ans = min(ans, j-i+1)
for h := 0; h < 32; h++ {
if nums[i]>>h&1 == 1 {
cnt[h]--
if cnt[h] == 0 {
s ^= 1 << h
}
}
}
}
}
if ans == n+1 {
return -1
}
return ans
}
26 changes: 26 additions & 0 deletions solution/3000-3099/3095.Shortest Subarray With OR at Least K I/Solution.java
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Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
class Solution {
public int minimumSubarrayLength(int[] nums, int k) {
int n = nums.length;
int[] cnt = new int[32];
int ans = n + 1;
for (int i = 0, j = 0, s = 0; j < n; ++j) {
s |= nums[j];
for (int h = 0; h < 32; ++h) {
if ((nums[j] >> h & 1) == 1) {
++cnt[h];
}
}
for (; s >= k && i <= j; ++i) {
ans = Math.min(ans, j - i + 1);
for (int h = 0; h < 32; ++h) {
if ((nums[i] >> h & 1) == 1) {
if (--cnt[h] == 0) {
s ^= 1 << h;
}
}
}
}
}
return ans > n ? -1 : ans;
}
}
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