feat: add solutions to lc problem: No.2041

solution/2000-2099/2041.Accepted Candidates From the Interviews/README.md

@@ -106,7 +106,9 @@ Rounds table:
 
 <!-- solution:start -->
 
-### 方法一
+### 方法一：连接表 + 分组 + 过滤
+
+我们可以将 `Candidates` 表和 `Rounds` 表按照 `interview_id` 进行连接，筛选出工作年限至少为 2 年的候选人，然后按照 `candidate_id` 进行分组，计算每个候选人的总分，最后筛选出总分大于 15 分的候选人。
 
 <!-- tabs:start -->
 
@@ -116,13 +118,26 @@ Rounds table:
 # Write your MySQL query statement below
 SELECT candidate_id
 FROM
-    Candidates AS c
-    LEFT JOIN Rounds AS r ON c.interview_id = r.interview_id
+    Candidates
+    JOIN Rounds USING (interview_id)
 WHERE years_of_exp >= 2
-GROUP BY c.interview_id
+GROUP BY 1
 HAVING SUM(score) > 15;
 ```
 
+#### Pandas
+
+```python
+import pandas as pd
+
+
+def accepted_candidates(candidates: pd.DataFrame, rounds: pd.DataFrame) -> pd.DataFrame:
+    merged_df = pd.merge(candidates, rounds, on="interview_id")
+    filtered_df = merged_df[merged_df["years_of_exp"] >= 2]
+    grouped_df = filtered_df.groupby("candidate_id").agg({"score": "sum"})
+    return grouped_df[grouped_df["score"] > 15].reset_index()[["candidate_id"]]
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/2000-2099/2041.Accepted Candidates From the Interviews/README_EN.md

@@ -105,7 +105,9 @@ Rounds table:
 
 <!-- solution:start -->
 
-### Solution 1
+### Solution 1: Join Tables + Grouping + Filtering
+
+We can join the `Candidates` table and the `Rounds` table based on `interview_id`, filter out candidates with at least 2 years of work experience, then group by `candidate_id` to calculate the total score for each candidate, and finally filter out candidates with a total score greater than 15.
 
 <!-- tabs:start -->
 
@@ -115,13 +117,26 @@ Rounds table:
 # Write your MySQL query statement below
 SELECT candidate_id
 FROM
-    Candidates AS c
-    LEFT JOIN Rounds AS r ON c.interview_id = r.interview_id
+    Candidates
+    JOIN Rounds USING (interview_id)
 WHERE years_of_exp >= 2
-GROUP BY c.interview_id
+GROUP BY 1
 HAVING SUM(score) > 15;
 ```
 
+#### Pandas
+
+```python
+import pandas as pd
+
+
+def accepted_candidates(candidates: pd.DataFrame, rounds: pd.DataFrame) -> pd.DataFrame:
+    merged_df = pd.merge(candidates, rounds, on="interview_id")
+    filtered_df = merged_df[merged_df["years_of_exp"] >= 2]
+    grouped_df = filtered_df.groupby("candidate_id").agg({"score": "sum"})
+    return grouped_df[grouped_df["score"] > 15].reset_index()[["candidate_id"]]
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/2000-2099/2041.Accepted Candidates From the Interviews/Solution.py

@@ -0,0 +1,8 @@
+import pandas as pd
+
+
+def accepted_candidates(candidates: pd.DataFrame, rounds: pd.DataFrame) -> pd.DataFrame:
+    merged_df = pd.merge(candidates, rounds, on="interview_id")
+    filtered_df = merged_df[merged_df["years_of_exp"] >= 2]
+    grouped_df = filtered_df.groupby("candidate_id").agg({"score": "sum"})
+    return grouped_df[grouped_df["score"] > 15].reset_index()[["candidate_id"]]

solution/2000-2099/2041.Accepted Candidates From the Interviews/Solution.sql

@@ -1,8 +1,8 @@
 # Write your MySQL query statement below
 SELECT candidate_id
 FROM
-    Candidates AS c
-    LEFT JOIN Rounds AS r ON c.interview_id = r.interview_id
+    Candidates
+    JOIN Rounds USING (interview_id)
 WHERE years_of_exp >= 2
-GROUP BY c.interview_id
+GROUP BY 1
 HAVING SUM(score) > 15;

solution/2000-2099/2042.Check if Numbers Are Ascending in a Sentence/README.md

@@ -241,35 +241,4 @@ bool areNumbersAscending(char* s) {
 
 <!-- solution:end -->
 
-<!-- solution:start -->
-
-### 方法二
-
-<!-- tabs:start -->
-
-#### Python3
-
-```python
-class Solution:
-    def areNumbersAscending(self, s: str) -> bool:
-        pre = i = 0
-        n = len(s)
-        while i < n:
-            if s[i].isdigit():
-                cur = 0
-                while i < n and s[i].isdigit():
-                    cur = cur * 10 + int(s[i])
-                    i += 1
-                if pre >= cur:
-                    return False
-                pre = cur
-            else:
-                i += 1
-        return True
-```
-
-<!-- tabs:end -->
-
-<!-- solution:end -->
-
 <!-- problem:end -->

solution/2000-2099/2042.Check if Numbers Are Ascending in a Sentence/README_EN.md

@@ -226,35 +226,4 @@ bool areNumbersAscending(char* s) {
 
 <!-- solution:end -->
 
-<!-- solution:start -->
-
-### Solution 2
-
-<!-- tabs:start -->
-
-#### Python3
-
-```python
-class Solution:
-    def areNumbersAscending(self, s: str) -> bool:
-        pre = i = 0
-        n = len(s)
-        while i < n:
-            if s[i].isdigit():
-                cur = 0
-                while i < n and s[i].isdigit():
-                    cur = cur * 10 + int(s[i])
-                    i += 1
-                if pre >= cur:
-                    return False
-                pre = cur
-            else:
-                i += 1
-        return True
-```
-
-<!-- tabs:end -->
-
-<!-- solution:end -->
-
 <!-- problem:end -->