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Create solution2.py to 013.Roman to Integer, 80ms #31

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Merged
merged 1 commit into from
Oct 20, 2018
Merged

Create solution2.py to 013.Roman to Integer, 80ms #31

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10 changes: 10 additions & 0 deletions solution/013.Roman to Integer/Solution2.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
class Solution(object):
def romanToInt(self, s):
dict = {'M':1000, 'D':500, 'C':100, 'L':50, 'X':10, 'V':5, 'I':1} #对应关系存在一个字典里
sum = 0
for i in range(len(s)-1):
if dict[s[i]] < dict[s[i+1]]: #这里小于是因为只会有一个减的存在，换句话说如果两个一样的出现，应该是加法
sum -= dict[s[i]]
else:
sum += dict[s[i]]
return sum+dict[s[-1]] #最后一位一定是加