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Oct 20, 2018
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Update solution 020 [README.md] #35

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14 changes: 7 additions & 7 deletions solution/020.Valid Parentheses/README.md
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Original file line number Diff line number Diff line change
Expand Up @@ -42,10 +42,10 @@
### 解法
遍历 string，遇到左括号，压入栈中；遇到右括号，从栈中弹出元素，元素不存在或者元素与该右括号不匹配，返回 false。遍历结束，栈为空则返回 true，否则返回 false。

因为字符串只包含"(){}[]",也可以进行特殊处理，用映射来做
因为字符串只包含"(){}[]",也可以进行特殊处理，用映射来做。

#### java
```
#### Java 版实现
```java
class Solution {
public boolean isValid(String s) {
if (s == null || s == "") {
Expand Down Expand Up @@ -85,8 +85,8 @@ class Solution {
}
```

#### C++
```
#### C++ 版实现
```cpp

class Solution {
public:
Expand Down Expand Up @@ -135,7 +135,7 @@ public:
}
};

//特殊
// 特殊
class Solution {
public:
bool isValid(string s) {
Expand Down Expand Up @@ -165,4 +165,4 @@ public:
}
};

```
```