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IEX.pry from another node #3392
@kdisneur I am travelling today and I just tried some sample implementation out. My first approach was that IEx.pry would automatically find another node, giving preference to local implementation.
However, we can only find nodes that have been connected upfront, so your code sample would only work if you called
The only other option I can think is to pass the node name directly as argument, something like:
Yup it makes sense and, anyway, trying to automatically find an IEX node would maybe be too much magic?
Just to be sure to understand it well, your proposition is:
This option looks pretty simple (in a user point of view) because it's easy to start an IEX with a specific name.
Just to clarify my comments, I was a little brief. I think we should support: