uses cal Unix program to print out the days in a month
Installation | Usage | Annotated source | License
You can just copy and paste the yyyymmdd.sh function or do the following
mkdir -p ~/.bash
cd ~/.bash
git clone git://github.com/fibo/yyyymmdd.git
Edit your ~/.bash_profile or ~/.profile and add the following
source ~/.bash/yyyymmdd/yyyymmdd.sh
On MacOS it is required to install coreutils, with brew do
brew install coreutils
Pass it year and month in YYYYMM format
$ yyyymmdd 201701
20170101
20170102
...
20170129
20170130
20170131
Optionally use FROM
and/or UNTIL
environment variables,
which are passed to date -d
GNU command, for example
UNTIL=now yyyymmdd 201701
UNTIL=yesterday yyyymmdd 201701
UNTIL="2 hours ago" yyyymmdd 201701
UNTIL=20170117 yyyymmdd 201701
FROM=20170117 yyyymmdd 201701
You can also use both across multiple yyyymmdd
command invocation
export FROM=20170117
export UNTIL=now
yyyymmdd 201701
yyyymmdd 201702
Create a yyyymmdd
bash function.
function yyyymmdd () {
Then split input into year and month.
YYYYMM=$1
if [ ${#YYYYMM} -ne 6 ]
then
echo "Param $YYYYMM is required in YYYYMM format" 1>&2
else
YYYY=${YYYYMM:0:4}
MM=${YYYYMM:4:2}
Use gdate
on MacOS, and date
on Linux.
Use cal to output days: on Linux it could highlight current day;
option cal -h
turns it off but it is not supported, nor necessary on MacOS.
CAL=$(which cal)
case "$OSTYPE" in
darwin*)
DATE=$(which gdate)
;;
linux*)
DATE=$(which date)
CAL="$CAL -h"
;;
esac
Handle FROM
and UNTIL
optional environment variables
YYYYMMDD_MIN=0
YYYYMMDD_MAX=99999999
if [ ! -z "$FROM" ]
then
YYYYMMDD_MIN=`$DATE --date "$FROM" +%Y%m%d`
fi
if [ ! -z "$UNTIL" ]
then
YYYYMMDD_MAX=`$DATE --date "$UNTIL" +%Y%m%d`
fi
Loop over days of month
for DAY in $($CAL $MM $YYYY | grep '^ *[0-9]')
do
DD=$(printf "%02d" $DAY)
YYYYMMDD=$YYYY$MM$DD
if [ $YYYYMMDD -gt $YYYYMMDD_MIN -a $YYYYMMDD -le $YYYYMMDD_MAX ]
then
echo $YYYY$MM$DD
fi
done
... and we are done!
fi
}
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