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实现 26 进制 #29

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francecil opened this issue Jan 9, 2020 · 1 comment
Closed

实现 26 进制 #29

francecil opened this issue Jan 9, 2020 · 1 comment
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JavaScript JS相关面试、笔试题,不涉及算法

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@francecil
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0->"A"
26->"AA"

@francecil francecil added the JavaScript JS相关面试、笔试题,不涉及算法 label Jan 9, 2020
@francecil
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francecil commented Jan 9, 2020

// number: 0~25 -> A~Z
function getLetter (number) {
  return String.fromCharCode(65 + number)
}
function convert26 (number) {
  // 类型检测
  if (typeof number !== "number" || Number.isNaN(number) || number === Infinity || number < 0) {
    console.warn("Type Error")
    return
  }
  // 将 1~26 -> 0~25 
  // 最开始的一次计算本身就是 0~25 自增补偿自减
  number++
  let result = ""
  while (number !== 0) {
    number--
    let mod = number % 26
    result = getLetter(mod) + result
    number = (number - mod) / 26
  }
  return result
}
convert26(0) //A
convert26(26) //AA

如果是 1~26 对应 A~Z 的话,代码改为如下

// number: 1~26 -> A~Z
function getLetter (number) {
  return String.fromCharCode(64 + number)
}
function convert26 (number) {
  // 类型检测
  if (typeof number !== "number" || Number.isNaN(number) || number === Infinity || number <= 0) {
    console.warn("Type Error")
    return
  }
  let result = ""
  while (number !== 0) {
    let mod = number % 26 || 26
    result = getLetter(mod) + result
    number = (number - mod) / 26
  }
  return result
}
convert26(1) //A
convert26(27) //AA

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Labels
JavaScript JS相关面试、笔试题,不涉及算法
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