用go编译win32的dll 怎么指定 _stdcall 的调用约束

[dzwvip]

What version of Go are you using (go version)?

$ go version

Does this issue reproduce with the latest release?

What operating system and processor architecture are you using (go env)?

go env Output

$ go env

What did you do?

What did you expect to see?

win32 程序调用 dll 默认的_stdcall方式, 用 go编译的dll 不能直接调用，我看 #32851 里面
https://github.com/code34/armago_x64 使用 C 函数 又包装了一下，可以使用了，但是又不想导出的函数名称后面 带有 @n ，该怎么解决 ？？

What did you see instead?

[zouhuigang]

我用这个库试了下，生成的armago_x64.h，没发现你说的参数有@n啊!

 extern void goRVExtensionVersion(char* p0, size_t p1);
 extern void goRVExtensionArgs(char* p0, size_t p1, char* p2, char** p3, int p4);
 extern void goRVExtension(char* p0, size_t p1, char* p2)

[ianlancetaylor]

Would somebody like to translate this into English? Thanks. I tried Google Translate but it wasn't clear.

[zouhuigang]

He said that DLL compiled with go could not be used by other Win32 programs.

[ianlancetaylor]

Thanks. Closing as dup of #22192.

[toy-lin]

The question is how to export WINAPI entry point without decoration.

As i know, this can export an c entry point, exported entry name would be "SayHello":

//export
func SayHello(){
  doSomething()
}

And #32851 offered a way to export WINAPI by using cgo, exported entry name would be "_SayHello@0":

#include <stdlib.h>
extern void goSayHello();
__declspec(dllexport) void __stdcall SayHello() {
  goSayHello();
}

But i want the entry name to be "SayHello", how could i do?

I have tried this answer 2 to add a comment in C code. The compile result is ok, but it didn't work(the entry name is still "_SayHello@0"):

#include <stdlib.h>
extern void goSayHello();
__declspec(dllexport) void __stdcall SayHello() {
  #pragma comment(linker, "/EXPORT:SayHelo=_SayHello@0")
  // or #pragma comment(linker, "/EXPORT:"__FUNCTION__"="__FUNCDNAME__)
  goSayHello();
}

Currently i am using CMAKE to build a dynamic library as intermediary. Adding a .def file to CmakeLists.txt works fine.
But i am still looking for a simple solution i could do this without an intermediary.

@dzwvip 请问你找到解决方案了吗?

[dzwvip]

ok  丁志伟

…

------------------ 原始邮件 ------------------ 发件人: wave <notifications@github.com&gt; 发送时间: 2020年2月7日 18:46 收件人: golang/go <go@noreply.github.com&gt; 抄送: dzwvip <dzwvip@qq.com&gt;, Mention <mention@noreply.github.com&gt; 主题: 回复：[golang/go] 用go编译win32的dll 怎么指定 _stdcall 的调用约束 (#34466) The question is how to export WINAPI entry point without decoration. As i know, this can export an c entry point, exported entry name would be "SayHello": //export func SayHello(){ doSomething() } And #32851 offered a way to export WINAPI by using cgo, exported entry name would be "_SayHello@0": ` #include <stdlib.h&gt; extern void goSayHello(char *output, size_t outputSize, char *input);

__declspec(dllexport) void __stdcall SayHello() { goSayHello(); } ` But i want the entry name to be SayHello, how could i do? I have tried https://inneka.com/programming/cpp/c-dll-export-decorated-mangled-names/ answer 2 to add a comment in C code. The compile result is ok, but it didn't work(the entry name is still "_SayHello@0"): `C #include <stdlib.h&gt; extern void goSayHello(char *output, size_t outputSize, char *input);

__declspec(dllexport) void __stdcall SayHello() { #pragma comment(linker, "/EXPORT:SayHelo=_SayHello@0") // or #pragma comment(linker, "/EXPORT:"FUNCTION"="FUNCDNAME) goSayHello(); } ` Currently i am using CMAKE to build a dynamic library as intermediary. Adding a .def file to CmakeLists.txt works fine.But i am still looking for a simple solution i could do this without an intermediary. @dzwvip 请问你找到解决方案了吗? — You are receiving this because you were mentioned. Reply to this email directly, view it on GitHub, or unsubscribe.