go/parser accepts illegal expressions #2155
Description
The go/parser accepts type literals instead if proper (value) expressions in several
cases; e.g.:
package p
func _() {
_ = []int{[]int}
_ = ([]int)
_ = a[[]int : []int]
_ = f([]int, []int)
_ <- []int
_ = []int(0)
select {
case _ <- []int:
}
}
is parsed w/o syntax errors.
There is a respective TODO in go/parser:1365 (parseExpr(lhs bool) ast.Expr method).