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calling Validator twice breaks multiple dateinput #150

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michan85 opened this Issue Aug 27, 2010 · 1 comment

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@michan85

Description

calling validator more than once causes only last dateinput on page to show popup.

i came accross this while dynamically adding fields to a form, and then calling
validator again to ensure those fields get validated.

Reproduce

Copy HTML

<form method="post" action="ui.php?action=validate" class="form"><h2>Add a field</h2><ul><li><label for="date">date</label><input type="date" required="required" name="date" class="date"></li><li><label for="date">date</label><input type="date" required="required" name="date" class="date"></li></ul><script type="text/javascript">
    (function(){

        $(":date").dateinput();
        $(":range").rangeinput();
        $("form")
            .validator()
            .submit(function(e) {

            var form = $(this);

            // client-side validation OK.
            if (!e.isDefaultPrevented()) {

                // submit with AJAX
                $.post("ui.php?action=validate", form.serialize(), function(resp) {

                    alert( resp );
                });

                // prevent default form submission logic
                e.preventDefault();     
            }
        });
    })();
</script></form>

from fire bug console call

  • $("form").validator()

then click on a date input control

  • they should not pop up.

Work Around

comment out this code in
validator.js -> Validator -> destroy:
//inputs.unbind(conf.inputEvent || '').unbind("change.V");

@tipiirai

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tipiirai Sep 10, 2010

Contributor

This is now fixed. here is the commit:

http://github.com/jquerytools/jquerytools/commit/3bf32e19998126e7bf0efa5ad80c9edb7dda0058

will be out in 1.2.5. Thanks!

Contributor

tipiirai commented Sep 10, 2010

This is now fixed. here is the commit:

http://github.com/jquerytools/jquerytools/commit/3bf32e19998126e7bf0efa5ad80c9edb7dda0058

will be out in 1.2.5. Thanks!

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