Balanced parentheses problem added #167
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adarshaacharya
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ashokdey
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Jul 26, 2020
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| if (prev < 0) return prev; | ||
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| if (char === '(') return ++prev; | ||
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| if (char === ')') return --prev; | ||
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| return prev; |
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Can we use a switch case here?
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I think switch case isn't needed here since we have to check two variables char & prev here. can i use ternary operator instead ?
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Something like this
return !string.split('').reduce((prev, char) => {
const result = prev < 0 ? prev : char === '(' ? ++prev : char === ')' ? --prev : prev;
return result;
}, 0);There was a problem hiding this comment.
The above snippet is not readable enough
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so, if else pattern will be fine right ? switch case will add more code since we have to check cases for prev & char.
| */ | ||
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| function balancedParantheses(string) { | ||
| return !string.split('').reduce(function(prev, char) { |
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How about an arrow function here?
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Issue no : #166
Solving balanced paratheses problem using reduce() method in ES6.