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hello , great library!
i'll use an example to describe my problem: i'm trying to unpack object Foo to object Bar. with the Map option of the SerializerContext - SerializationMethod but an exception is thrown:
Foo {
prop string X,Y,
prop int A
}
Bar { prop X,Y,Z }
is there a way to get X and Y values in the new object and leave Z null or default (and ignore A completly)?
thank you
The text was updated successfully, but these errors were encountered:
I'm sorry, it is a bug.
I forgot to implement to skip unknown value on deserializing map, so serializer try to the value as key string.
I'll fix it soon. Thank you your report.
hello , great library!
i'll use an example to describe my problem: i'm trying to unpack object Foo to object Bar. with the Map option of the SerializerContext - SerializationMethod but an exception is thrown:
Foo {
prop string X,Y,
prop int A
}
Bar { prop X,Y,Z }
is there a way to get X and Y values in the new object and leave Z null or default (and ignore A completly)?
thank you
The text was updated successfully, but these errors were encountered: