don't overrite arg's type if it's annotated explicitly #10424
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amtoine
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Sep 19, 2023
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i really like these changes, small bug right but super confusing, thanks @WindSoilder 🙏
i propose to wait for after the release 😉
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hardfau1t
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Dec 14, 2023
# Description Fixes: nushell#10410 So the following script is possible: ```nushell def a [b: any = null] { let b = ($b | default "default_b"); } a "given_b" ``` ## About the change When parsing signature, and nushell meets something like `a: any`, it force the parser to treat `a` as `any` type. This is what `arg_explicit_type` means, it's only set when we goes into `ParseMode::TypeMode`, and it will be reset to `false` if the token goes to next argument. so, when we have something like this: `def a [b: any = null] { $b }`, the type of `$b` won't be overwritten. But if we have something like this: `def a [b = null] { $b }`, the type of `$b` is not annotated, so we make it to be `nothing`(which is the type of null)
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Description
Fixes: #10410
So the following script is possible:
About the change
When parsing signature, and nushell meets something like
a: any, it force the parser to treataasanytype. This is whatarg_explicit_typemeans, it's only set when we goes intoParseMode::TypeMode, and it will be reset tofalseif the token goes to next argument.so, when we have something like this:
def a [b: any = null] { $b }, the type of$bwon't be overwritten.But if we have something like this:
def a [b = null] { $b }, the type of$bis not annotated, so we make it to benothing(which is the type of null)