Optimize solution #17
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qiyuangong
reviewed
Oct 7, 2020
| x /= 10; | ||
| if (rev > Integer.MAX_VALUE/10 || (rev == Integer.MAX_VALUE / 10 && pop > 7)) return 0; |
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Need to explain 7 and -8 with comments.
qiyuangong
reviewed
Oct 7, 2020
| res = res * 10 + x % 10; | ||
| if (res > Integer.MAX_VALUE || res < Integer.MIN_VALUE) | ||
| return 0; | ||
| int pop = x % 10; |
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Also, you can comment original solution (which is very concise), and add this new solution.
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