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[fixed] Prevent unintended register and unregister #808 #1040
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Perhaps a question for you, @diasbruno, as it's not strictly related to this change -- it looks like the only actual use of
this.state.isOpen
is this block:Is that correct? 🤔 Is there a way we could accomplish the programmatic focus of the content without maintaining a
this.state.isOpen
variable alongsidethis.props.isOpen
? The simplification may be nice, if so.There was a problem hiding this comment.
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The state inside the modal is used to manage the timed transition (sync'd with CSS).
When the isOpen flag is changed from true to false, the internal state is true.
react-modal will wait the css transition N milliseconds, then set to false
(same when you are openning).
When the transition has finished, we then do the tear down any other resources
(applied css names to document.body and others).
I always wanted to implement the transition mechanism using css transition events,
but never had a change to see the support for it.
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Ahh! Obrigado pela explicação. :)
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It would be more reliable than setting timers to manage the internal state.
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That would be cool! I did see this v4 issue about that: #993
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This proposed fix does not work if the modal is closed with a timeout.
isOpen
will befalse
when we get here, soafterClose()
won't run and the body class will be left on the DOM.There was a problem hiding this comment.
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@gillesbouvier-qz Could you please provide me with an example? It would be helpful. Thanks!
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Are you foregoing support for this?
If you still want to support the above, I believe
isOpen
will befalse
during unmounting andafterClose()
won't run leaving the body class in place (andonAfterClose()
won't run either). Using theisOpen
props seems unsafe to me, as only the modal component should control when it is open or closed.Maybe I'm missing something?
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Wouldn't this solve both problems at once?
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It solves the problem for in my testcase:
the idea being that we always want
afterClose()
to run at least once even when unmounting.