Skip to content

Multicall pagination #421

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 2 commits into from
Nov 10, 2021
Merged

Multicall pagination #421

Changes from all commits
Commits
Show all changes
2 commits
Select commit Hold shift + click to select a range
8b96f74
Multicall pagination
ChaituVR Nov 10, 2021
6145cb3
Update utils.ts
bonustrack Nov 10, 2021
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
26 changes: 19 additions & 7 deletions src/utils.ts
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -47,14 +47,26 @@ export async function multicall(
);
const itf = new Interface(abi);
try {
const [, res] = await multi.aggregate(
calls.map((call) => [
call[0].toLowerCase(),
itf.encodeFunctionData(call[1], call[2])
]),
options || {}
const max = options.limit || 1000;
const pages = Math.ceil(calls.length / max);
const promises: any = [];
Array.from(Array(pages)).forEach((x, i) => {
const callsInPage = calls.slice(max * i, max * (i + 1));
promises.push(
multi.aggregate(
callsInPage.map((call) => [
call[0].toLowerCase(),
itf.encodeFunctionData(call[1], call[2])
]),
options || {}
)
);
});
let results: any = await Promise.all(promises);
results = results.reduce((prev: any, [, res]: any) => prev.concat(res), []);
return results.map((call, i) =>
itf.decodeFunctionResult(calls[i][1], call)
);
return res.map((call, i) => itf.decodeFunctionResult(calls[i][1], call));
} catch (e) {
return Promise.reject(e);
}
Expand Down