fix: When parameter "value" is json string, JsonParser should convert json string to Object directly.

[bourne7]

when parameter "value" is json string:

{
    "name": "foo"
}

current code will convert it to json string with escaped quotes:

{\\"name\\":\\"foo\\"}

following code will fail to parse it from escaped json string to object.

[sobychacko]

@bourne7 Could you add a unit test to verify these changes? in JsonParserTests.

[bourne7]

sure

[bourne7]

sy, i find that this problem has been fixed in this commit:

18ae16e Ahmed Maruf 81756975+ohmaruf@users.noreply.github.com on 2025-05-27 at 16:56
fix(json): prevent double-serialization of already valid JSON strings in JsonParser.toJson

[bourne7]

Additional improvements:

modification on 05-28 added isValidJson method, it actually attempts deserialization to determine if the string is JSON type. In fact, this could be optimized - change it to immediately return the object if successful, avoiding double deserialization.

In most cases, Model returns a JSON string, so this optimization can eliminate one deserialization step in the majority of scenarios.

[sobychacko]

We still need a unit test to validate the changes.

[bourne7]

@sobychacko unittest added ;)