xmldoc
lets you parse XML documents with ease. It's a pure-JavaScript, one-file XML document class with a single dependency on the excellent sax
parser.
For more on why I wrote this class, see the blog post.
npm install xmldoc
Or just download the repository and include it in your node_modules
directly. Or just download the single JS file!
var xmldoc = require('../lib/xmldoc');
var document = new xmldoc.XmlDocument("<some>xml</some>");
// do things
The primary exported class is XmlDocument
, which you'll use to consume your XML text. XmlDocument
contains a hierarchy of XmlElement
instances representing the XML structure.
Both XmlElement
and XmlDocument
contain the same members and methods you can call to traverse the document or a subtree.
name
- the node name, like "tat" for<tat>
. XML "namespaces" are ignored by the underlying sax-js parser, so you'll simply get "office:body" for<office:body>
.attr
- an object dict containing attribute properties, likebookNode.attr.title
for<book title="...">
.val
- the string "value" of the node, if any, like "world" for<hello>world</hello>
.children
- an array ofXmlElement
children of the node.firstChild
,lastChild
- pretty much what it sounds like; null if no childrenline
,column
,position
,startTagPosition
- information about the element's original position in the XML string.
Each member defaults to a sensible "empty" value like {}
for attr
, []
for children
, and ""
for val
.
All methods with child
in the name operate only on direct children; they do not do a deep/recursive search.
It's important to note that xmldoc
is designed for when you know exactly what you want from your XML file. For instance, it's great for parsing API responses with known structures, but it's not great at teasing things out of HTML documents from the web.
If you need to do lots of searching through your XML document, I highly recommend trying a different library like node-elementtree.
Similar to underscore's each
method, it will call func(child, index, array)
for each child of the given node.
Pass it the name of a child node and it will search for and return the first one found, or undefined
.
Like childNamed
but returns all matching children in an array, or []
.
Searches for the first child with the given attribute value. You can omit value
to just find the first node with the given attribute defined at all.
Searches for a specific "path" using dot notation. Example:
<book>
<author>
<name isProper="true">George R. R. Martin</name>
...
</author>
...
</book>
If you just want the <name>
node and you have the XmlElement
for the <book>
node, you can say:
var nameNode = bookNode.descendantWithPath("author.name"); // return <name> node
Just like descendantWithPath
, but goes deeper and extracts the val
of the node. Example:
var authorName = bookNode.valueWithPath("author.name"); // return "George R. R. Martin"
You can also use the @
character to request the value of a particular attribute instead:
var authorIsProper = bookNode.valueWithPath("author.name@isProper"); // return "true"
This is not XPath! It's just a thing I made up, OK?
This is just an override of the standard JavaScript method, it will give you a string representation of your XML document or element. Note that this is for debugging only! It is not guaranteed to always output valid XML.
The default implementation of toString()
, that is, the one you get when you just console.log("Doc: " + myDoc)
will pretty-print the XML with linebreaks and indents. You can pass a couple options to control the output:
xml.toString({compressed:true}) // strips indents and linebreaks
xml.toString({trimmed:true}) // trims long strings for easier debugging
Putting it all together:
var xml = "<author><name>looooooong value</name></author>";
console.log("My document: \n" + new XmlDocument(xml).toString(trimmed:true))
Prints:
My Document:
<hello>
loooooooo…
</hello>
Feel free to file issues or hit me up on Twitter.