time.clock() removed in Python3.8 replace with time.perf_counter()

[Metallicow]

time.clock() has been deprecated in py3.3 and removed in py3.8

https://docs.python.org/3/whatsnew/3.8.html

The function time.clock() has been removed, after having been deprecated since Python 3.3: 
use time.perf_counter() or time.process_time() instead, depending on your requirements, 
to have well-defined behavior. (Contributed by Matthias Bussonnier in bpo-36895.)

timeit test on py3

def Test1():
    t = time.perf_counter()
def Test2():
    t = time.process_time()

Microsoft Windows 7 x64
Python 3.8.1 x64

------------------------------------------
Timeit Test - 1000000 times
Test1:[0.20428928500000154, 0.1874606649999997, 0.1864975280000003, 0.18765649500000237, 0.18984756899999766]
Test2:[0.45273342399999805, 0.45695258800000005, 0.45270879199999925, 0.4579686850000009, 0.45511786500000184]

Winner: Test1
Loser: Test2

And the alternative Py2 test just to see test results diff on 2/3 and x32/x64.

def Test1():
    t = time.clock()

Microsoft Windows 7 x64
Python 2.7.17 x32

------------------------------------------
Timeit Test - 1000000 times
Test1:[0.1861580078093728, 0.16879239639197288, 0.1702609131900069]

It appears time.perf_counter() is the function we want to replace time.clock() with.

The purposed fix in framemanager.py:
Since python 2 is depricated now, 3 will become more popular, so hotpatch py2 since phoenix didn't run on less than py3.3 anyhow.

In framemanager.py imports section

import time
import sys
if sys.version_info[0] == 2:  # hotpatch clock which is removed in py3.8
    time.perf_counter = time.clock

In framemanager.py AddPane1 method

        # if the pane's name identifier is blank, create a random string
        if pinfo.name == "" or already_exists:
            pinfo.name = ("%s%08x%08x%08x") % (pinfo.window.GetName(), int(time.time()),
                                               int(time.perf_counter()), len(self._panes))

@RobinD42 I've tested this on 2and3 in my agw copy. Does this look good to you to submit a PullREQz?

[RobinD42]

Yes, go ahead.