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cv.lmmlasso "penalized" argument #3
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can you please paste in a comment the output from |
- Session info --------------------------------------------------------------------------
setting value
version R version 3.5.3 (2019-03-11)
os Windows >= 8 x64
system x86_64, mingw32
ui RStudio
language (EN)
collate English_United States.1252
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date 2019-03-28
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it looks like the error is coming from is your data a single object or a few objects that is being input into for example lmmlasso::lmmlasso(x = X, y = y, z = Z, grp = grp, lambda = lambda, pdMat = pdMat) if it is a set of objects please put them in a list say file.create('mydata.txt')
dput(l,file='mydata.txt') then drag and drop that data into a comment, this way I can reproduce the problem on my computer. |
I appreciate the help, but this is human subjects research so the data cannot be shared publicly. I will contact my supervisor to ask about sharing it with you directly, but I cannot post it here. |
that is ok. can you reproduce the same issue with a generic matrix? |
I made up the code below - it follows a similar structure to my dataset but the content is relative nonsense. I've been trying to replicate the problem, but the error I'm now getting says that y needs to be numeric (error copied at bottom). The problem is that my original elements are numeric and R will not let me reconfigure it. If I can get it to recognize that the outcome is numeric, I suspect the original problem will be replicated. I'm sorry to spring this new issue on you! Apologies for not creating a file as above, but this runs fine when copied and pasted. ClientID <- c(rep("1",5), rep("2",5), rep("3",5), rep("4",5), rep("5",5), rep("6",5))
Age <- as.matrix(c(rep(9,5), rep(11,5), rep(10,5), rep(13,5), rep(15,5), rep(12,5)), ncol = 1)
Gender <- as.matrix(factor(c(rep(1,5),rep(2,5),rep(1,5),rep(2,5),rep(1,5), rep(2,5)), labels = c("Boy", "Girl")), ncol = 1)
Medication <- as.matrix(factor(c(rep(2,5),rep(2,5),rep(1,5),rep(1,5),rep(1,5), rep(2,5)), labels = c("no", "yes")), ncol = 1)
Treatment <- as.matrix(factor(c(rep(1,5),rep(2,5),rep(2,5),rep(2,5),rep(1,5), rep(1,5)), labels = c("usual care", "CBT")), ncol = 1)
Treatment_site <- as.matrix(c(rep(1,5),rep(3,5),rep(2,5), rep(2,5), rep(1,5), rep(3,5)), ncol = 1)
Day <- as.matrix(c(0, 20, 40, 60, 80, 0, 25, 50, 75, 100, 0, 22, 40, 65, 80, 0, 33, 50, 79, 95, 0, 16, 41, 69, 88, 0, 30, 60, 90, 120), ncol = 1)
Symptoms <-c(8, 7, 6, 5, 4, 14, 12, 11, 8, 6, 9, 7, 9, 7, 5, 6, 4, 5, 3, 3, 8, 6, 3, 3, 2, 11, 14, 13, 11, 10)
Data <-as.matrix(cbind(Age, Gender, Medication, Treatment, Day))
Test_Matrix <- cbind(Symptoms, Data, Treatment_site)
colnames(Test_Matrix) <- c( "y", "X1", "X2", "X3", "X4", "X5", "Z")
rownames(Test_Matrix) <- ClientID
cv.lmmlasso(Test_Matrix) Error in lmmlasso.default(x = X, y = y, z = Z, grp = grp, lambda = lambda[i], : |
that is ok. i'll try to reproduce using this example. |
Thank you. I am concerned that the problem may relate to the data's complexity - my input includes a model.matrix() output that contains 3-way interactions. Since the example does not contain interaction elements, I am wondering if that may not have been incorporated into the function. |
that may be a limitation of |
That's not the case - if I run lmmlasso() using my data (not with everything in a singular matrix, as in cv.lmmlasso, but with x, y, z, and grp specified) and input a random value for lambda, the function works. |
good to know, that narrows it down for me. i'll get back to you with a solution for that test data. |
Thank you so much. If the error doesn't appear with the data as I sent it, would you mind using model.matrix( ~.^3, data) to generate those 3-way interactions and to see if the problem occurs in that context? |
it looks like there is a problem in ClientID <- rep(1:6,each=5)
Age <- rep(c(9,11,10,13,15,12),each=5)
Gender <- rep(c(0,1),each=5,time=3)
Medication <- rep(c(1,1,0,0,0,1),each=5)
Treatment <- rep(c(0,1,1,1,0,0),each=5)
Treatment_site <- rep(c(1,3,2,2,1,3),each=5)
Day <- c(0, 20, 40, 60, 80, 0, 25, 50, 75, 100, 0, 22, 40, 65, 80, 0, 33, 50, 79, 95, 0, 16, 41, 69, 88, 0, 30, 60, 90, 120)
Symptoms <- c(8, 7, 6, 5, 4, 14, 12, 11, 8, 6, 9, 7, 9, 7, 5, 6, 4, 5, 3, 3, 8, 6, 3, 3, 2, 11, 14, 13, 11, 10)
Data <- as.matrix(cbind(Age, Gender, Medication, Treatment, Day))
Test_Matrix <- cbind(Symptoms, Data, Treatment_site)
colnames(Test_Matrix) <- c("y", sprintf("X%s",1:5), "Z")
rownames(Test_Matrix) <- ClientID
lmmen::cv.lmmlasso(Test_Matrix)
#> Error in optL1(y, x[, -1], model = "linear", fold = 10, trace = FALSE): could not find function "optL1"
data <- as.matrix(Test_Matrix)
y <- matrix(data[ , grepl('^y' , colnames(data))] , ncol = 1)
X <- cbind(rep(1 , nrow(data)) , data[ , grepl('^X' , colnames(data))])
Z <- cbind(rep(1 , nrow(data)) , data[ , grepl('^Z' , colnames(data))])
grp <- factor(row.names(data))
pdMat <- "pdSym"
lmmlasso::lmmlasso(x = X,
y = y,
z = Z,
grp = grp,
lambda = 0,
pdMat = pdMat)
#> Error in optL1(y, x[, -1], model = "linear", fold = 10, trace = FALSE): could not find function "optL1" Created on 2019-03-31 by the reprex package (v0.2.1) Session infodevtools::session_info()
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Dear Jonathan Sidi, I am having the same error with cv.lmmlasso as in this thread (#3): cv.lmmlasso(dat.cv,lambda = seq(0, 500, 5)) Below the two configurations I tried: R version 3.3.2 (2016-10-31) locale: attached base packages: other attached packages: loaded via a namespace (and not attached): ——————— R version 3.6.3 (2020-02-29) Matrix products: default locale: attached base packages: other attached packages: loaded via a namespace (and not attached): Could you help me? Kind regards, Niels Verburg |
I still cannot run the simple reproducible example from above when directly calling lmmlasso. cv.lmmlasso is just a wrapper on that package. I would suggest you open an issue for that package. Thanks |
(post to follow up on email)
when inputting a matrix into cv.lmmlasso(), the error below appears
Error in .checkinput(match.call(), parent.frame()) :
missing values in "penalized" argument
but "penalized" is not an argument in cv.lmmlasso or lmmlasso, so it is not clear what this is referring to or how to fix it.
Thank you.
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