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30 changes: 30 additions & 0 deletions problems/0102.二叉树的层序遍历.md
Original file line number Diff line number Diff line change
Expand Up @@ -271,6 +271,36 @@ func levelOrder(root *TreeNode) [][]int {

return res
}

/**
102. 二叉树的层序遍历:使用切片模拟队列,易理解
*/
func levelOrder(root *TreeNode) (res [][]int) {
if root == nil {
return
}

curLevel := []*TreeNode{root} // 存放当前层节点
for len(curLevel) > 0 {
nextLevel := []*TreeNode{} // 准备通过当前层生成下一层
vals := []int{}

for _, node := range curLevel {
vals = append(vals, node.Val) // 收集当前层的值
// 收集下一层的节点
if node.Left != nil {
nextLevel = append(nextLevel, node.Left)
}
if node.Right != nil {
nextLevel = append(nextLevel, node.Right)
}
}
res = append(res, vals)
curLevel = nextLevel // 将下一层变成当前层
}

return
}
```

javascript代码:
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