Skip to content
This repository was archived by the owner on Aug 17, 2024. It is now read-only.
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension


Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
63 changes: 61 additions & 2 deletions 2-exercises/task.md
Original file line number Diff line number Diff line change
Expand Up @@ -7,6 +7,7 @@ In this homework, you are going to work with an ecommerce database. In this data
Below you will find a set of tasks for you to complete to set up a database for an e-commerce app.

To submit this homework write the correct commands for each question here:

```sql


Expand Down Expand Up @@ -35,16 +36,74 @@ Open the file `cyf_ecommerce.sql` in VSCode and examine the SQL code. Take a pie
Once you understand the database that you are going to work with, solve the following challenge by writing SQL queries using everything you learned about SQL:

1. Retrieve all the customers' names and addresses who live in the United States

select \* from customers where country = 'United States';

2. Retrieve all the customers in ascending name sequence

select \* from customers order by name asc;

3. Retrieve all the products whose name contains the word `socks`

select \* from products where product_name like '%socks%';

4. Retrieve all the products which cost more than 100 showing product id, name, unit price and supplier id.

select p.id,p.product_name,p_a.unit_price,p_a.supp_id from products p join product_availability p_a on (p.id = p_a.prod_id) where p_a.unit_price > 100;

5. Retrieve the 5 most expensive products

select \* from products join product_availability on products.id = product_availability.prod_id order by unit_price desc limit 5;

6. Retrieve all the products with their corresponding suppliers. The result should only contain the columns `product_name`, `unit_price` and `supplier_name`

select p.product_name, p_a.unit_price,s.supplier_name from products p join product_availability p_a on (p.id = p_a.prod_id) join suppliers s on (s.id = p_a.supp_id);

7. Retrieve all the products sold by suppliers based in the United Kingdom. The result should only contain the columns `product_name` and `supplier_name`.
8. Retrieve all orders, including order items, from customer ID `1`. Include order id, reference, date and total cost (calculated as quantity * unit price).

select p.product_name , s.supplier_name
from products p join product_availability p_a on (p_a.prod_id = p.id) join suppliers s on (s.id = p_a.supp_id) where s.country = 'United Kingdom'

8. Retrieve all orders, including order items, from customer ID `1`. Include order id, reference, date and total cost (calculated as quantity \* unit price).

select o.id , o.order_reference , o.order_date , (o_i.quantity \* p_a.unit_price) as total_cost
from orders o join order_items o_i on (o.id = o_i.order_id)
join product_availability p_a on (p_a.prod_id = o_i.product_id) where o.customer_id = 1;

9. Retrieve all orders, including order items, from customer named `Hope Crosby`

select o.id, o.order_reference , o_i.product_id, p.product_name , o_i.quantity from orders o
join order_items o_i on (o.id = o_i.order_id) join products p on (o_i.product_id = p.id)
join customers on (customers.id = o.customer_id)
where customers.name='Hope Crosby';

10. Retrieve all the products in the order `ORD006`. The result should only contain the columns `product_name`, `unit_price` and `quantity`.

select p.product_name , p_a.unit_price , o_i.quantity from orders o
join order_items o_i on (o_i.order_id = o.id)
join products p on (o_i.product_id = p.id)
join product_availability p_a on (p_a.prod_id = o_i.product_id) where o.order_reference = 'ORD006';

11. Retrieve all the products with their supplier for all orders of all customers. The result should only contain the columns `name` (from customer), `order_reference`, `order_date`, `product_name`, `supplier_name` and `quantity`.

select c.name , o.order_reference, o.order_date, p.product_name, s.supplier_name, o_i.quantity from customers c
join orders o on (c.id = o.customer_id)
join order_items o_i on (o.id = o_i.order_id)
join products p on (p.id = o_i.product_id)
join suppliers s on (o_i.supplier_id = s.id)

12. Retrieve the names of all customers who bought a product from a supplier based in China.
13. List all orders giving customer name, order reference, order date and order total amount (quantity * unit price) in descending order of total.

select distinct c.name from customers c
join orders on (orders.customer_id = c.id)
join order_items on (order_items.order_id = orders.id)
join suppliers on (suppliers.id = order_items.supplier_id)
where suppliers.country = 'China'

13. List all orders giving customer name, order reference, order date and order total amount (quantity \* unit price) in descending order of total.

select c.name , o.order_reference, o.order_date, (o_i.quantity \* p_a.unit_price) as order_total_amount from customers c
join orders o on (c.id = o.customer_id)
join order_items o_i on (o_i.order_id = o.id)
join product_availability p_a on (o_i.product_id = p_a.prod_id)
order by order_total_amount desc;
1 change: 1 addition & 0 deletions 3-projects/.gitignore
Original file line number Diff line number Diff line change
@@ -0,0 +1 @@
node_modules
Loading