Update Q1.sql

Author: Somnath-pandit

Q1.sql

@@ -10,4 +10,128 @@ WITH User_Post_Count AS (
 
 SELECT AVG(Post_Count) Avg_Posts_Per_User
 FROM User_Post_Count
+	
+
+-- 2. Find the top 5 most used hashtags.
+USE ig_clone;
+SELECT tag_name, COUNT(*) tags_count
+FROM tags
+GROUP BY tag_name
+ORDER BY tags_count
+LIMIT 5
+
+
+-- 3. Find users who have liked every single photo on the site.
+
+USE ig_clone;
+SELECT u.id, u.username
+FROM users u 
+INNER JOIN photos p 
+	ON u.id = p.user_id
+LEFT JOIN likes l 
+	ON p.id = l.photo_id
+GROUP BY u.id, u.username
+HAVING COUNT(DISTINCT p.id) = COUNT(l.photo_id)
+ORDER BY u.id
+
+
+-- 4. Retrieve a list of users along with their usernames and the 
+-- rank of their account creation, ordered by the creation date in ascending order.
+
+SELECT *,
+		RANK() OVER (ORDER BY created_at) ac_creation_rank
+FROM users
+ORDER BY created_at
+
+
+
+-- 5. List the comments made on photos with their comment texts, 
+-- photo URLs, and usernames of users who posted the comments. Include the comment count for each photo
+USE ig_clone;
+
+SELECT c.comment_text, p.image_url, u.username,
+	   (SELECT COUNT(*) 
+        FROM comments c2 
+        WHERE c2.photo_id = c.photo_id) count_of_comment
+FROM comments c
+INNER JOIN photos p 
+	ON c.user_id = p.user_id
+INNER JOIN users u 
+	ON p.user_id = u.id
+
+
+
+
+-- 6. For each tag, show the tag name and the number of 
+-- photos associated with that tag. Rank the tags by the number of photos in descending order.
+USE ig_clone;
+
+SELECT t.tag_name, COUNT(pt.photo_id) count_of_photo
+FROM tags t 
+LEFT JOIN photo_tags pt 
+	ON t.id = pt.tag_id 
+GROUP BY t.tag_name
+ORDER BY count_of_photo
+
+
+
+-- 7. List the usernames of users who have posted photos along 
+-- with the count of photos they have posted. Rank them by the number of photos in descending order.
+
+
+USE ig_clone;
+SELECT u.username, COUNT(p.id) AS photo_count
+FROM users u
+LEFT JOIN photos p 
+	ON u.id = p.user_id
+GROUP BY u.username
+ORDER BY photo_count DESC;
+
+
+
+-- 8. Display the username of each user along with the
+-- creation date of their first posted photo and the creation date of their next posted photo.
+
+USE ig_clone;
+
+WITH UserPhotoDates AS (
+    SELECT
+        p.user_id,
+        MIN(p.created_at)  first_photo_date,
+        LEAD(MIN(p.created_at)) OVER (PARTITION BY p.user_id ORDER BY MIN(p.created_at))  next_photo_date
+    FROM photos p
+    GROUP BY p.user_id
+)
+
+SELECT
+    u.username,
+    upd.first_photo_date,
+    upd.next_photo_date
+FROM users u
+INNER JOIN UserPhotoDates upd
+	ON u.id = upd.user_id;
+
+
+
+-- 9. For each comment, show the comment text, the username of the commenter, 
+-- and the comment text of the previous comment made on the same photo.
+
+WITH CommentWithPrevious AS (
+    SELECT
+		u.username AS commenter_username,
+        c1.comment_text AS current_comment_text,
+			LAG(c1.comment_text) OVER (PARTITION BY c1.photo_id ORDER BY c1.created_at) AS previous_comment_text
+    FROM comments c1
+    INNER JOIN users u 
+		ON c1.user_id = u.id
+)
+
+SELECT
+    current_comment_text,
+    commenter_username,
+    previous_comment_text
+FROM
+    CommentWithPrevious;
+
+