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Linked Listify
Sar Champagne Bielert edited this page Apr 20, 2024
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1 revision
Unit 5 Session 2 (Click for link to problem statements)
Understand what the interviewer is asking for by using test cases and questions about the problem.
- How should the function handle an empty list?
- If the input list
lst
is empty, the function should returnNone
since there would be no nodes to create.
- If the input list
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Convert an array of values into a linked list, starting with the first value as the head and linking subsequent values.
1) Check if the input list `lst` is empty and return `None` if true.
2) Create the head of the linked list with the first element of `lst`.
3) Traverse the remaining elements of `lst`, creating a new node for each and linking it to the list.
4) Return the head of the newly formed linked list.
- Forgetting to handle the case of an empty input list, which should return
None
. - Errors in linking nodes could lead to incorrect or incomplete linked list structure.
def list_to_linked_list(lst):
if not lst: # Check if the array is empty
return None
head = Node(lst[0]) # Create the head node with the first element
current = head
for value in lst[1:]: # Iterate over the rest of the elements
current.next = Node(value) # Create a new node and link it
current = current.next
return head