Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

proposal: cmd/generate: Be able to run directives that *don't* match a specified expression #38687

Open
xtonyjiang opened this issue Apr 27, 2020 · 0 comments
Labels
Milestone

Comments

@xtonyjiang
Copy link

@xtonyjiang xtonyjiang commented Apr 27, 2020

We currently have the -run flag, but I believe it is currently impossible to supply a regular expression that would allow for excluding a certain expression (due to no lookaheads in Go's regex syntax). Being able to exclude expressions would be useful if we want to exclude certain directives that are time-consuming and are not needed in the moment, and we want to run a large amount of other directives, so that it would be impractical to simply run go generate multiple times with different -run flags.

I think one way to implement this could be an additional flag. Similar to grep's --invert-match flag, we could do something like:

go generate -invertmatch -run="my excluded pattern" ./...

Alternatively, we could also have a different flag that is used instead of -run, like:

go generate -runexcept="my excluded pattern" ./...

Here, supplying both -runexcept and -run would be invalid.

@gopherbot gopherbot added this to the Proposal milestone Apr 27, 2020
@gopherbot gopherbot added the Proposal label Apr 27, 2020
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Projects
None yet
Linked pull requests

Successfully merging a pull request may close this issue.

None yet
2 participants
You can’t perform that action at this time.