Skip to content

Update chisel-book-chinese.tex #4

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 1 commit into
base: master
Choose a base branch
from
Open

Update chisel-book-chinese.tex #4

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
4 changes: 2 additions & 2 deletions chisel-book-chinese.tex
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -2864,8 +2864,8 @@ \subsection{The Nerd Counter}
例如，我们想要设计一个超级优化的计数器。
一个标准的计数器需要以下资源：一个寄存器，一个加法器（或是减法器），一个比较器。
我们不能再寄存器或是加法器做很多。如果我们向上数，我们需要比较一个目标数，这是一个字符。
比较器可以从0开始反向生成一个字符，然后一个大的与们。
当我们向下数零的时候，比较器是一个大的或非们，这个从AISC的角度是更加便宜的。
比较器可以从0开始反向生成一个字符，然后一个大的与门。
当我们向下数零的时候，比较器是一个大的或非门，这个从AISC的角度是更加便宜的。
在FPGA，逻辑来源于查找表，所以在比较1或是0的时候就没什么区别了，此时向上数和向下数对于资源的要求是一样的。


Expand Down