[DOC] Clarify example for Enumerable#each_with_object

[ColinTheRobot]

Problem

Colleague asked what the splat did in this example and I don't think it does anything but maybe tries to handle an edge case that doesn't exist in the provided for example.

What changed

• assign h to the hash used in the example similar to earlier examples
• remove unnecessary splat in front of element

[Maumagnaguagno]

You could even skip element: h.each_with_object({}) {|(k, v), h| h[v] = k }.
Perhaps it is a better idea to not assign before the example, otherwise there are two hvariables (one outside and one inside block, each pointing to a different hash):
{foo: 0, bar: 1, baz: 2}.each_with_object({}) {|(k, v), h| h[v] = k }

[ColinTheRobot]

You could even skip element: h.each_with_object({}) {|(k, v), h| h[v] = k }. Perhaps it is a better idea to not assign before the example, otherwise there are two hvariables (one outside and one inside block, each pointing to a different hash): {foo: 0, bar: 1, baz: 2}.each_with_object({}) {|(k, v), h| h[v] = k }

That's a good shout 🤔 A lot of stuff happening in this method. Will have another go with this feedback in mind