Quoted application of varargs method shows an incorrect syntax

## minimized code

```Scala
val expr = Expr(List(1, 2, 3))
println(expr.show) // prints “scala.List.apply[scala.Int](1, 2, 3: _*)”
```

Try it live: https://scastie.scala-lang.org/E1LT4UfBTgepAcHdkSALCA

## expectation

`expr.show == "scala.List.apply[scala.Int](1, 2, 3)"`

(no trailing “: _*”)