🟢 Solve problem 242

Author: AF2B

swift/242.swift

@@ -0,0 +1,20 @@
+class Solution {
+    func isAnagram(_ s: String, _ t: String) -> Bool {
+        if s.count != t.count {
+            return false
+        }
+
+        var countS: [Character: Int] = [:]
+        var countT: [Character: Int] = [:]
+
+        for char in s {
+            countS[char, default: 0] += 1
+        }
+
+        for char in t {
+            countT[char, default: 0] += 1
+        }
+
+        return countS == countT
+    }
+}